Chapter 14: Problem 46
Find the Cauchy-Riemann equations in polar coordinates. Hint : \(z=r e^{i \theta}, f(z)=u(r, \theta)+i \tau(r, \theta) .\) Follow the method of equations \((2.3)\) and \((2.4) .\)
Short Answer
Expert verified
The Cauchy-Riemann equations in polar coordinates are \( \frac{\text{∂u}}{\text{∂r}} = \frac{1}{r}\frac{\text{∂τ}}{\text{∂θ}} \) and \( \frac{\text{∂τ}}{\text{∂r}} = -r\frac{\text{∂u}}{\text{∂θ}}. \)
Step by step solution
01
Express the Function in Polar Coordinates
Given the function in Cartesian coordinates as f(z) = u(x, y) + i v(x, y), convert it using the polar coordinates where z = r e^{iθ}. This implies using f(z) = u(r, θ) + i τ(r, θ).
02
Define Partial Derivatives
Express the partial derivatives of u and v in terms of r and θ: \( \frac{\text{∂u}}{\text{∂r}} \text{,} \frac{\text{∂u}}{\text{∂θ}} \text{,} \frac{\text{∂τ}}{\text{∂r}} \text{, and} \frac{\text{∂τ}}{\text{∂θ}}.\)
03
Convert Cartesian Cauchy-Riemann Equations
Convert the equations from Cartesian to polar coordinates. The Cartesian Cauchy-Riemann equations are: \( \frac{\text{∂u}}{\text{∂x}} = \frac{\text{∂v}}{\text{∂y}}, \) and \( \frac{\text{∂u}}{\text{∂y}} = -\frac{\text{∂v}}{\text{∂x}}. \)
04
Use Chain Rule for Partial Derivatives
Express the partial derivatives of x and y with respect to r and θ using the chain rule: \( x = r \text{cosθ}, \) and \( y = r \text{sinθ}. \) So, \( \frac{\text{∂u}}{\text{∂x}} = \frac{\text{∂u}}{\text{∂r}} \frac{\text{∂r}}{\text{∂x}} + \frac{\text{∂u}}{\text{∂θ}} \frac{\text{∂θ}}{\text{∂x}}, \) and similarly for other partial derivatives.
05
Simplify Using Polar Coordinates
Substitute the partial derivatives of r and θ with respect to x and y into the equations: \( \frac{\text{∂r}}{\text{∂x}} = \text{cosθ}, \) \( \frac{\text{∂r}}{\text{∂y}} = \text{sinθ}, \) \( \frac{\text{∂θ}}{\text{∂x}} = -\frac{\text{sinθ}}{r}, \) and \( \frac{\text{∂θ}}{\text{∂y}} = \frac{\text{cosθ}}{r}. \)
06
Derive the Cauchy-Riemann Equations in Polar Form
Combine and simplify the equations to get: \[ \frac{\text{∂u}}{\text{∂r}} = \frac{1}{r}\frac{\text{∂τ}}{\text{∂θ}}, \] \[ \frac{\text{∂τ}}{\text{∂r}} = -r\frac{\text{∂u}}{\text{∂θ}}. \]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
complex functions
Complex functions are functions that take complex numbers as inputs and provide complex numbers as outputs. A complex number is expressed in the form: \( z = x + iy \), where \( x \) is the real part and \( iy \) is the imaginary part.
In the context of the Cauchy-Riemann equations, we often express these functions as \( f(z) = u(x, y) + iv(x, y) \), where \( u(x, y) \) and \( v(x, y) \) represent the real and imaginary parts of the function, respectively.
When considering complex functions in polar coordinates, we utilize the transformation \( z = re^{i\theta} \), which converts the function \( f(z) \) to a form involving \( r \) and \( \theta \). Typically, this transformation leads to an expression like \( f(z) = u(r, \theta) + i\tau(r, \theta) \), enabling us to explore the behavior of complex functions more easily in different coordinate systems.
In the context of the Cauchy-Riemann equations, we often express these functions as \( f(z) = u(x, y) + iv(x, y) \), where \( u(x, y) \) and \( v(x, y) \) represent the real and imaginary parts of the function, respectively.
When considering complex functions in polar coordinates, we utilize the transformation \( z = re^{i\theta} \), which converts the function \( f(z) \) to a form involving \( r \) and \( \theta \). Typically, this transformation leads to an expression like \( f(z) = u(r, \theta) + i\tau(r, \theta) \), enabling us to explore the behavior of complex functions more easily in different coordinate systems.
partial derivatives
Partial derivatives are essential when studying the behavior of multivariable functions, like \( f(x, y) \). They measure how a function changes as the input varies along one of its dimensions while holding other dimensions constant.
For complex functions, we often deal with the derivatives \( \frac{\text{∂u}}{\text{∂x}} \) and \( \frac{\text{∂v}}{\text{∂y}} \) in Cartesian coordinates. But when we switch to polar coordinates, we look at \( \frac{\text{∂u}}{\text{∂r}} \), \( \frac{\text{∂u}}{\text{∂\theta}} \), \( \frac{\text{∂\tau}}{\text{∂r}} \), and \( \frac{\text{∂\tau}}{\text{∂\theta}} \).
The chain rule helps us convert the expressions for partial derivatives between different coordinate systems. For instance, knowing that \( x = r\text{cos}\theta \) and \( y = r\text{sin}\theta \), we can express the Cartesian partial derivatives in terms of polar coordinates.
For complex functions, we often deal with the derivatives \( \frac{\text{∂u}}{\text{∂x}} \) and \( \frac{\text{∂v}}{\text{∂y}} \) in Cartesian coordinates. But when we switch to polar coordinates, we look at \( \frac{\text{∂u}}{\text{∂r}} \), \( \frac{\text{∂u}}{\text{∂\theta}} \), \( \frac{\text{∂\tau}}{\text{∂r}} \), and \( \frac{\text{∂\tau}}{\text{∂\theta}} \).
The chain rule helps us convert the expressions for partial derivatives between different coordinate systems. For instance, knowing that \( x = r\text{cos}\theta \) and \( y = r\text{sin}\theta \), we can express the Cartesian partial derivatives in terms of polar coordinates.
polar coordinates
Polar coordinates are a two-dimensional coordinate system where each point on a plane is determined by a distance \( r \) from a reference point and an angle \( \theta \) from a reference direction.
Polar coordinates provide a useful alternative to Cartesian coordinates, especially in problems exhibiting radial symmetry. The transformation from Cartesian to polar coordinates is given by:
\( x = r \text{cos} \theta \)
\( y = r \text{sin} \theta \)
Using these relations, we can express complex functions and their derivatives in polar form. This transformation simplifies analyzing problems involving circular or spiral patterns.
In deriving the Cauchy-Riemann equations in polar coordinates, we convert the Cartesian form of the equations, making use of substitutions and simplifications to obtain:
\( \frac{\text{∂u}}{\text{∂r}} = \frac{1}{r} \frac{\text{∂\tau}}{\text{∂\theta}} \)
\( \frac{\text{∂\tau}}{\text{∂r}} = -r \frac{\text{∂u}}{\text{∂\theta}} \).
Polar coordinates provide a useful alternative to Cartesian coordinates, especially in problems exhibiting radial symmetry. The transformation from Cartesian to polar coordinates is given by:
\( x = r \text{cos} \theta \)
\( y = r \text{sin} \theta \)
Using these relations, we can express complex functions and their derivatives in polar form. This transformation simplifies analyzing problems involving circular or spiral patterns.
In deriving the Cauchy-Riemann equations in polar coordinates, we convert the Cartesian form of the equations, making use of substitutions and simplifications to obtain:
\( \frac{\text{∂u}}{\text{∂r}} = \frac{1}{r} \frac{\text{∂\tau}}{\text{∂\theta}} \)
\( \frac{\text{∂\tau}}{\text{∂r}} = -r \frac{\text{∂u}}{\text{∂\theta}} \).