Chapter 6: Problem 10
A thin uniform circular disc has mass \(M\) and radius \(a\). (a) Prove that its moment of inertia about an axis perpendicular to its plane and passing through its centre is \(\frac{1}{2} M a^{2}\). (b) Prove that the moment of inertia of the same disc about a diameter is \(\frac{1}{4} \mathrm{Ma}^{2}\). This is an example of the general result for planar bodies that the moment of inertia of the body about an axis perpendicular to the plane is equal to the sum 211of the moments of inertia about two perpendicular axes lying in the plane: in an obvious notation $$ I_{z}=\int r^{2} d m=\int\left(x^{2}+y^{2}\right) d m=\int x^{2} d m+\int y^{2} d m=I_{y}+I_{x} $$
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.