Chapter 4: Problem 1
Sum the even numbers between 1000 and 2000 inclusive.
Short Answer
Expert verified
Sum is 751500.
Step by step solution
01
- Identify the range of even numbers
The problem asks to sum the even numbers between 1000 and 2000, including both endpoints. Determine the first and last even numbers in this range. Since 1000 and 2000 are both even, they will be included in the sum.
02
- Use the formula for the sum of an arithmetic series
The even numbers between 1000 and 2000 form an arithmetic series with the first term (a) equal to 1000, the last term (l) equal to 2000, and the common difference (d) equal to 2. The formula to find the sum of an arithmetic series is: \[ S = \frac{n}{2} \times (a + l) \ \] where \(n\) is the number of terms.
03
- Find the number of terms
Use the formula for the number of terms in an arithmetic series: \[ n = \frac{l - a}{d} + 1 \ \]. Substituting the values: \[ n = \frac{2000 - 1000}{2} + 1 = 501 \ \] Thus, there are 501 terms.
04
- Calculate the sum
Substitute the values back into the sum formula: \[ S = \frac{501}{2} \times (1000 + 2000) \ \] \[ S = 250.5 \times 3000 = 751500 \ \] Therefore, the sum of even numbers between 1000 and 2000 is 751500.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
arithmetic series
An arithmetic series is a sequence of numbers where the difference between consecutive terms is constant. This difference is called the common difference, denoted by \(d\). In the case of even numbers, the common difference \(d\) is 2 because each even number is 2 units apart from the next. For example, in the series 2, 4, 6, 8, the common difference is 2.
To identify an arithmetic series, look for a pattern of repeated addition. This type of series provides a structured way to address various problems, including the summation of sequences.
Understanding arithmetic series is crucial since they are foundational elements in mathematics, especially useful when dealing with large sets of incrementally increasing numbers.
To identify an arithmetic series, look for a pattern of repeated addition. This type of series provides a structured way to address various problems, including the summation of sequences.
Understanding arithmetic series is crucial since they are foundational elements in mathematics, especially useful when dealing with large sets of incrementally increasing numbers.
sum formula
The sum formula for an arithmetic series is a useful tool to find the total sum of several terms without summing each one individually. The formula is:
\[ S = \frac{n}{2} \times (a + l) \]
- \(S\) is the sum of the series.
- \(n\) is the number of terms.
- \(a\) is the first term.
- \(l\) is the last term.
This formula helps simplify the process of finding the sum, especially when dealing with large numbers of terms.
For example, to find the sum of the even numbers from 1000 to 2000, we use this formula directly. Given that the first term \(a\) is 1000 and the last term \(l\) is 2000, we first calculate the number of terms \(n\). After calculating \(n\), we can plug into the formula to efficiently find the sum.
\[ S = \frac{n}{2} \times (a + l) \]
- \(S\) is the sum of the series.
- \(n\) is the number of terms.
- \(a\) is the first term.
- \(l\) is the last term.
This formula helps simplify the process of finding the sum, especially when dealing with large numbers of terms.
For example, to find the sum of the even numbers from 1000 to 2000, we use this formula directly. Given that the first term \(a\) is 1000 and the last term \(l\) is 2000, we first calculate the number of terms \(n\). After calculating \(n\), we can plug into the formula to efficiently find the sum.
number of terms
To find the number of terms in an arithmetic series, you can use the following formula:
\[ n = \frac{l - a}{d} + 1 \]
- \(n\) is the number of terms.
- \(l\) is the last term.
- \(a\) is the first term.
- \(d\) is the common difference.
For the problem of finding the sum of even numbers between 1000 and 2000, including both 1000 and 2000, we first identify the number of terms in this series.
Let's find \(n\):
1. First term \(a\) = 1000
2. Last term \(l\) = 2000
3. Common difference \(d\) = 2
Plug in these values:
\[ n = \frac{2000 - 1000}{2} + 1 = 501 \]
Thus, there are 501 terms in this series. Knowing the number of terms, we can now use the sum formula to find the total sum. This formula is particularly helpful in systematically solving problems involving sequences.
\[ n = \frac{l - a}{d} + 1 \]
- \(n\) is the number of terms.
- \(l\) is the last term.
- \(a\) is the first term.
- \(d\) is the common difference.
For the problem of finding the sum of even numbers between 1000 and 2000, including both 1000 and 2000, we first identify the number of terms in this series.
Let's find \(n\):
1. First term \(a\) = 1000
2. Last term \(l\) = 2000
3. Common difference \(d\) = 2
Plug in these values:
\[ n = \frac{2000 - 1000}{2} + 1 = 501 \]
Thus, there are 501 terms in this series. Knowing the number of terms, we can now use the sum formula to find the total sum. This formula is particularly helpful in systematically solving problems involving sequences.