The equation of an ellipse in plane polar coordinates \(r, \theta\), with one of
its foci at the origin, is
$$
\frac{l}{r}=1-\epsilon \cos \theta
$$
where \(l\) is a length (that of the latus rectum) and \(\epsilon(0<\epsilon<1)\)
is the eccentricity of the ellipse. Express the area of the ellipse as an
integral around the unit circle in the complex plane, and show that the only
singularity of the integrand inside the circle is a double pole at
\(z_{0}=\epsilon^{-1}-\left(\epsilon^{-2}-1\right)^{1 / 2}\)
By setting \(z=z_{0}+\xi\) and expanding the integrand in powers of \(\xi\), find
the residue at \(z_{0}\) and hence show that the area is equal to \(\pi
l^{2}\left(1-\epsilon^{2}\right)^{-3 / 2}\). (In terms of the semi-axes \(a\) and
\(b\) of the ellipse, \(l=b^{2} / a\) and
\(\left.\epsilon^{2}=\left(a^{2}-b^{2}\right) / a^{2} .\right)\)