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Use the derivative method to obtain as a second solution of Bessel's equation for the case when \(v=0\) the following expression: $$ J_{0}(z) \ln z-\sum_{n=1}^{\infty} \frac{(-1)^{n}}{(n !)^{2}}\left(\sum_{r=1}^{n} \frac{1}{r}\right)\left(\frac{z}{2}\right)^{2 n}, $$ given that the first solution is \(J_{0}(z)\) as specified by (16.63).

Short Answer

Expert verified
The second solution is \( J_{0}(z) \ln z - \sum_{n=1}^\rightarrow \frac{(-1)^n}{(n!)^2} \sum_{r=1}^{n}\frac{1}{r}\bigg(\big(\frac{z}{2}\big)^{2n}\bigg) \

Step by step solution

01

- Recognize the Primary and Secondary Solutions

Bessel's equation of order zero has two solutions. The first solution is given as \( J_{0}(z)\). The task is to find the second solution using the derivative method.
02

- Define the Derivative Method

In this method, let's use the fact that if \( J_{v}(z) \) is a solution of Bessel's equation, another linearly independent solution can be found as \[ Y_{v}(z) = C J_{v}(z) \text{ln} z + \text{sum of series terms}. \]
03

- Apply the Derivative Expansion

For \( v = 0 \), the second solution can be written as \[ Y_{0}(z) = C J_{0}(z) \text{ln} z + \text{sum of series terms} \] where the series accounts for non-logarithmic components.
04

- Substitute into Bessel's Equation

Differentiate \( J_{0}(z) \) term by term to find \( J_{0}'(z) \). Use the logarithmic derivative technique and integrate resulting series.
05

- Obtain the Series Expression

Integrate the above series term by term to obtain: \[ J_{0}(z) \text{ln} z - \text{series sum} \] Summation over \( n \) and \( r \) to derive the necessary terms from integrations.
06

- Formulate the Solution

That completes the derivative method solution to find the unique second solution.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Derivative Method
The Derivative Method is a powerful tool for finding independent solutions to differential equations, including Bessel's equation. Bessel's equation of order zero can be written as:
\frac{d^2 y}{dz^2} + \frac{1}{z}\frac{dy}{dz} + \big(1 - \frac{u^2}{z^2}\big)y = 0 For the case when \(u = 0\), the first solution, \(J_0(z)\), is well-known. However, there exists a secondary solution involving a logarithmic term.
For Bessel’s equation, if \(J_ν(z)\) is a solution, a linearly independent solution, \( Y_ν(z)\), can be found using:
Y_ν(z) = C J_ν(z) \text{ln} z + \text{sum of series terms}. This method involves differentiating the known solution \(J_0(z)\) and integrating the terms step-by-step to form the second solution involving the logarithmic component and a series expansion.
Series Expansion
Series Expansion is integral in accurately expressing the second solution of Bessel's equation. After expressing the primary solution with a logarithmic component, we need to determine the remaining series terms without logarithms.
For \( v = 0 \), the second solution can be written as:
\[ Y_{0}(z) = C J_{0}(z) \text{ln} z + \text{sum of series terms} \]
To determine these series terms, use the method of differentiation and integration. Differentiate \( J_{0}(z) \) term by term, yielding expressions with terms involving \( \frac{z}{2}^{2n} \). Integrating each term results in a series sum:
\frac{(-1)^{n}}{(n!)^2}\bigg(\frac{z}{2}\bigg)^{2n}\bigg(\frac{1}{r}\bigg), which forms part of the secondary solution to Bessel's equation. By summing over all integral values of n and r, the series accurately reconstructs the solution.
Independent Solutions
Finding independent solutions to Bessel’s equation is essential for a complete set of solutions. Generally, differential equations of second order require two linearly independent solutions.

For Bessel's equation of order zero, \(J_{0}(z)\) is the primary solution. The second solution, found through the Derivative Method, includes logarithmic terms and compensating series expansions:

\(J_{0}(z) \text{ln} z - \text{sum of series terms}\).
The general form of the second solution thus combines logarithmic differentiation of \(J_{0}(z)\) with integrated series terms, producing a function orthogonal and independent of \(J_{0}(z)\). This ensures completeness in solving Bessel’s equation, crucial for practical applications and deeper mathematical insights.

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Most popular questions from this chapter

Change the independent variable in the equation $$ \frac{d^{2} f}{d z^{2}}+2(z-a) \frac{d f}{d z}+4 f=0 $$ from \(z\) to \(x=z-\alpha\), and find two independent series solutions, expanded about \(x=0\), of the resulting equation. Deduce that the general solution of \((*)\) is $$ f(z, \alpha)=A(z-\alpha) e^{-(z-\alpha)^{2}}+B \sum_{m=0}^{\infty} \frac{(-4)^{m} m !}{(2 m) !}(z-\alpha)^{2 m} $$ with \(A\) and \(B\) arbitrary constants.

Find two power series solutions about \(z=0\) of the differential equation $$ \left(1-z^{2}\right) y^{\prime \prime}-3 z y^{\prime}+\lambda y=0 $$ Deduce that the value of \(\lambda\) for which the corresponding power series becomes an \(N\) th-degree polynomial \(U_{N}(z)\) is \(N(N+2)\). Construct \(U_{2}(z)\) and \(U_{3}(z)\).

Verify that \(z=0\) is a regular singular point of the equation $$ z^{2} y^{\prime \prime}-\frac{3}{2} z y^{\prime}+(1+z) y=0 $$ and that the indicial equation has roots 2 and \(1 / 2 .\) Show that the general solution is $$ \begin{aligned} y(z)=& 6 a_{0} z^{2} \sum_{n=0}^{\infty} \frac{(-1)^{n}(n+1) 2^{2 n} z^{n}}{(2 n+3) !} \\ &+b_{0}\left(z^{1 / 2}+2 z^{3 / 2}-\frac{z^{1 / 2}}{4} \sum_{n=2}^{\infty} \frac{(-1)^{n} 2^{2 n} z^{n}}{n(n-1)(2 n-3) !}\right). \end{aligned} $$

Obtain the recurrence relations for the solution of Legendre's equation (16.35) in inverse powers of \(z\), i.e. set \(y(z)=\sum a_{n} z^{\sigma-n}\), with \(a_{0} \neq 0 .\) Deduce that if \(\ell\) is an integer then the series with \(\sigma=\ell\) will terminate and hence converge for all \(z\) whilst that with \(\sigma=-(\ell+1)\) does not terminate and hence converges only for \(|z|>1\).

A charge \(+2 q\) is situated at the origin and charges of \(-q\) are situated at distances \(\pm a\) from it along the polar axis. By relating it to the generating function for the Legendre polynomials, show that the electrostatic potential \(\Phi\) at a point \((r, \theta, \phi)\) with \(r>a\) is given by $$ \Phi(r, \theta, \phi)=\frac{2 q}{4 \pi \epsilon_{0} r} \sum_{s=1}^{\infty}\left(\frac{a}{r}\right)^{2 s} P_{2 s}(\cos \theta). $$

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