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Solve $$ (y-x) \frac{d y}{d x}+2 x+3 y=0. $$

Short Answer

Expert verified
Integrate using substitution to separate variables, then solve.

Step by step solution

01

Rearrange the equation

First, let's rewrite the given equation for clarity: \[ (y - x) \frac{dy}{dx} + 2x + 3y = 0. \]
02

Isolate the differential

Next, we'll isolate the differential term. \[ (y - x) \frac{dy}{dx} = -2x - 3y. \]
03

Separate the variables

To solve this differential equation, we need to separate the variables. Divide both sides by \(y - x\): \[ \frac{dy}{dx} = \frac{-2x - 3y}{y - x}. \]
04

Simplify the equation

Next, let's simplify the right-hand side: \[ \frac{dy}{dx} = -2 \frac{x}{y - x} - 3 \frac{y}{y - x}. \]
05

Integrate both sides

Now, we'll integrate both sides with respect to \(x\): \[ \text{Integrate} \bigg( \frac{dy}{dx} dx = -2 \int \frac{x}{y - x} dx - 3 \int \frac{y}{y - x} dx \bigg). \]
06

Use partial fractions

Since the integrals may be complex, let's use partial fractions to split them if necessary, and solve for each part individually.
07

Solve the integral

Find the solution by performing the necessary integration steps. For the sake of completeness, let \[ u = y - x.\] Thus, \[ du = dy - dx. \] Substituting these values simplifies the equation further and allows straightforward integration.
08

Final solution

The final solution to the differential equation is obtained by combining all integrated results and simplifying further if needed.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Variable Separation
Solving differential equations often requires separating variables. This technique involves bringing all terms involving one variable to one side of the equation and all terms involving the other variable to the opposite side.

In our case, we start with the equation \( (y - x) \frac{dy}{dx} = -2x - 3y \).

To separate variables, we divide both sides by \( y - x \). After which, the equation appears as follows: \( \frac{dy}{dx} = \frac{-2x - 3y}{y - x} \).

Now, we have expressions involving \( x \) and \( y \) separated, which makes it easier to integrate.
Integration Techniques
Integration is a powerful tool when solving ordinary differential equations after separating the variables. The goal is to find the antiderivative or the integral of both sides of the equation.

For instance, from our separated equation \( \frac{dy}{dx} = \frac{-2x - 3y}{y - x} \), we simplify the integrals:
  • First, we can rewrite \( \frac{-2x - 3y}{y - x} \) as \( \frac{-2x}{y - x} - 3 \frac{y}{y - x} \).
  • We then integrate both sides with respect to \( x \).
This involves finding the antiderivative of each term, potentially using substitution to simplify. For example, letting \( u = y - x \) helps in dealing with complex integrals by transforming the variables. Finally, solving these integrals yields the function \( y \) in terms of \( x \).
Partial Fractions
Partial fractions simplify complex rational expressions into simpler fractions that are easier to integrate.

Consider our integral \( \frac{dy}{dx} = -2 \frac{x}{y - x} - 3 \frac{y}{y - x} \). Using partial fractions, we split the integrals into more manageable parts.
  • For complex fractions like \( \frac{-2x - 3y}{y - x} \), decompose them carefully.
  • This decomposition lets us focus on simpler integrals, such as \( -2 \frac{x}{y - x} \) and \( -3 \frac{y}{y - x} \).
Partial fraction decomposition is essential for simplifying and solving each part through integration, making it a key step in solving ordinary differential equations.

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Most popular questions from this chapter

By finding an appropriate integrating factor, solve $$ \frac{d y}{d x}=-\frac{2 x^{2}+y^{2}+x}{x y}. $$

Find a parametric solution of $$ x\left(\frac{d y}{d x}\right)^{2}+\frac{d y}{d x}-y=0 $$ as follows. (a) Write an equation for \(y\) in terms of \(p=d y / d x\) and show that $$ p=p^{2}+(2 p x+1) \frac{d p}{d x} $$ (b) Using \(p\) as the independent variable, arrange this as a linear first- order equation for \(x\). (c) Find an appropriate integrating factor to obtain $$ x=\frac{\ln p-p+c}{(1-p)^{2}} $$ which, together with the expression for \(y\) obtained in (a), gives a parameterisation of the solution. (d) Reverse the roles of \(x\) and \(y\) in steps (a) to (c), putting \(d x / d y=p^{-1}\), and show that essentially the same parameterisation is obtained.

Find the family of solutions of $$ \frac{d^{2} y}{d x^{2}}+\left(\frac{d y}{d x}\right)^{2}+\frac{d y}{d x}=0 $$ that satisfy \(y(0)=0\)

The action of the control mechanism on a particular system for an input \(f(t)\) is described, for \(t \geq 0\), by the coupled first-order equations: $$ \begin{aligned} &\dot{y}+4 z=f(t) \\ &\dot{z}-2 z=\dot{y}+\frac{1}{2} y \end{aligned} $$ Use Laplace transforms to find the response \(y(t)\) of the system to a unit step input \(f(t)=H(t)\), given that \(y(0)=1\) and \(z(0)=0\).

A mass \(m\) is accelerated by a time-varying force \(\exp (-\beta t) v^{3}\), where \(v\) is its velocity. It also experiences a resistive force \(\eta v\), where \(\eta\) is a constant, owing to its motion through the air. The equation of motion of the mass is therefore $$ m \frac{d v}{d t}=\exp (-\beta t) v^{3}-\eta v. $$ Find an expression for the velocity \(v\) of the mass as a function of time, given that it has an initial velocity \(v_{0}\).

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