Chapter 13: Problem 10
In many applications in which the frequency spectrum of an analogue signal is required, the best that can be done is to sample the signal \(f(t)\) a finite number of times at fixed intervals and then use a discrete Fourier transform \(F_{k}\) to estimate discrete points on the (true) frequency spectrum \(\tilde{f}(\omega)\). (a) By an argument that is essentially the converse of that given in section \(13.1\), show that, if \(N\) samples \(f_{n}\), beginning at \(t=0\) and spaced \(t\) apart, are taken, then \(f(2 \pi k /(N \tau)) \approx F_{k} \tau\) where $$ F_{k}=\frac{1}{\sqrt{2 \pi}} \sum_{n=0}^{N-1} f_{n} e^{-2 \pi m k / N} $$ (b) For the function \(f(t)\) defined by $$ f(t)= \begin{cases}1 & \text { for } 0 \leq t<1 \\ 0 & \text { otherwise }\end{cases} $$ from which eight samples are drawn at intervals of \(\tau=0.25\), find a formula for \(\left|F_{k}\right|\) and evaluate it for \(k=0,1, \ldots, 7 .\) (c) Find the exact frequency spectrum of \(f(t)\) and compare the actual and estimated values of \(\sqrt{2 \pi}|\hat{f}(\omega)|\) at \(\omega=k \pi\) for \(k=0,1, \ldots, 7\). Note the relatively good agreement for \(k<4\) and the lack of agreement for larger values of \(k\)
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