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Use Stokes' Theorem to evaluate the integral $$ \int_{C}-y^{3} d x+x^{3} d y-z^{3} d z $$ for \(C\) the (positively oriented) curve of intersection between the cylinder \(x^{2}+y^{2}=1\) and the plane \(x+y+z=1\)

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Step by step solution

01

Find the Vector Field

The vector field \(\mathbf{F}\) can be written as: \[\mathbf{F} = -y^{3} \mathbf{i} + x^{3} \mathbf{j} - z^{3} \mathbf{k}\] By weighting the differential elements \(dx\), \(dy\), and \(dz\) by the physical quantities \(-y^3\), \(x^3\), and \(-z^3\) respectively.
02

Curl of the Vector Field

The curl of the field \(\mathbf{F}\) is calculated using \(\nabla \times \mathbf{F}\). The curl results to: \[\nabla \times \mathbf{F} = \begin{vmatrix} \mathbf{i} & \mathbf{j} & \mathbf{k} \ \frac{\partial}{\partial x} & \frac{\partial}{\partial y} & \frac{\partial}{\partial z} \ -y^{3} & x^{3} & -z^{3} \end{vmatrix} = (3z^2\mathbf{i} - 0\mathbf{j} - 3x^{2}\mathbf{k}) = 3z^{2}\mathbf{i} - 3x^{2}\mathbf{k}\]
03

Application of Stokes' Theorem

Integrate the flux of the curl over a disk \(D\) that lies in the plane \(z = 1 - x - y\), and is enclosed by the given curve \(C\): \[\int_{C} \mathbf{F} \cdot d\mathbf{r} = \iint_D (\nabla \times \mathbf{F}) \cdot d\mathbf{S}\] where the surface \(S\) is positively oriented towards the upward direction \(n = \mathbf{k}\), the disk \(D\) has polar coordinates \(x = r\cos(\theta)\), \(y = r\sin(\theta)\), and \(z = 1 - r\). So our double integral simplifies into: \[\iint_D (\nabla \times \mathbf{F}) \cdot d\mathbf{S} =\iint_D [3r^2(1-r)\mathbf{i} - 3r^2\cos^2(\theta)\mathbf{k} ] \cdot \mathbf{k} \, rdrd\theta = -3 \int^{2\pi}_{0} \int^1_0 r^4 \cos^2(\theta) \, dr d\theta\]
04

Solve the Integral

Since the integrand does not depend on \(r\), we get \[-3 \int^{2\pi}_{0} \cos^2(\theta) d\theta \int^1_0 r^4 \, dr = -3 \cdot \frac{1}{2} \cdot \frac{1}{5} = -3/10 \] Note here that the integral of \(r^4\) dr from 0 to 1 is \(1/5\), and the integral of \(\cos^2(\theta)\) d\theta from 0 to \(2\pi\) is \(\pi\), hence you get the factor of \(\pi/2\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Vector Field
A vector field assigns a vector to every point in a specific region of space. Picture a field of arrows where each arrow represents a vector in the field. In our example, the vector field \( \mathbf{F} \) is given by:\[ \mathbf{F} = -y^{3} \mathbf{i} + x^{3} \mathbf{j} - z^{3} \mathbf{k} \]Here, each component of the vector corresponds to one dimension in space, aligning with the coordinates \( x, y, \) and \( z \). The vector component \(-y^3\mathbf{i}\) acts along the x-direction, \(x^3\mathbf{j}\) along the y-direction, and \(-z^3\mathbf{k}\) along the z-direction.When you deal with vector fields in calculus, you explore how these vectors change or flow in space. Vector fields are core to understanding concepts like fluid flow, electromagnetic fields, and heat distribution.
Curl of a Vector Field
The curl of a vector field gives us an idea of the rotation or swirling strength of the field at any point. It tells us about the tendency to rotate about an axis. To find the curl \( abla \times \mathbf{F} \), we use a determinant involving partial derivatives:\[ abla \times \mathbf{F} = \begin{vmatrix} \mathbf{i} & \mathbf{j} & \mathbf{k} \frac{\partial}{\partial x} & \frac{\partial}{\partial y} & \frac{\partial}{\partial z} \-y^{3} & x^{3} & -z^{3} \end{vmatrix} = 3z^{2}\mathbf{i} - 3x^{2}\mathbf{k} \]The result of this operation is a new vector field that points in the direction of the axis of rotation, with a magnitude that tells us how strongly the points in the field are swirling around that axis.
Surface Integral
A surface integral is a method of integrating a scalar or a vector field over a surface. It’s like laying a net over the surface and summing up the contributions from each piece of the net. The surface integral is crucial in applying Stokes' Theorem.In our context, we have a surface integral:\[ \iint_D (abla \times \mathbf{F}) \cdot d\mathbf{S} \]Here, \(d\mathbf{S}\) is the vector element of surface area, and the integral is over the region \(D\), a disk in our specific example. The components of \(abla \times \mathbf{F} \) are used in this integral to determine the net flow across the surface, contributing to the vortex or swirling patterns over the region.
Cylindrical Coordinates
To describe surfaces, curves, or bodies in three dimensions, it's often helpful to use cylindrical coordinates, especially when dealing with symmetrical shapes like cylinders. Cylindrical coordinates use a mixture of regular Cartesian and circular coordinates with \(r, \theta,\) and \(z\).- \(r\) is the radial distance from the axis of symmetry (usually the z-axis).- \(\theta\) is the angular coordinate, representing the rotation about the z-axis.- \(z\) is the height along the z-axis.In our problem, transforming the surface integral into cylindrical coordinates simplifies integration, as the cylinder’s equation \(x^2 + y^2 = 1\) directly converts to \(r = 1\), and \(z = 1 - x - y\) can also be adapted accordingly. This transformation reflects the adaptability and utility of cylindrical coordinates in evaluating integrals more conveniently.

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Most popular questions from this chapter

Write the following using \(\epsilon_{i j k}\) notation and simplify if possible. a. \(\mathbf{C} \times(\mathbf{A} \times(\mathbf{A} \times \mathbf{C}))\) b. \(\nabla \times(\nabla \times \mathbf{A})\) c. \(\nabla \times \nabla \phi\).

Zaphod Beeblebrox was in trouble after the infinite improbability drive caused the Heart of Gold, the spaceship Zaphod had stolen when he was President of the Galaxy, to appear between a small insignificant planet and its hot sun. The temperature of the ship's hull is given by \(T(x, y, z)=\) \(e^{-k\left(x^{2}+y^{2}+z^{2}\right)}\) Nivleks. He is currently at \((1,1,1)\), in units of globs, and \(k=2\) globs \(^{-2}\). (Check the Hitchhikers Guide for the current conversion of globs to kilometers and Nivleks to Kelvin.) a. In what direction should he proceed so as to decrease the temperature the quickest? b. If the Heart of Gold travels at \(e^{6}\) globs per second, then how fast will the temperature decrease in the direction of fastest decline?

Consider the integral \(\int_{C} y^{2} d x-2 x^{2} d y\). Evaluate this integral for the following curves: a. \(C\) is a straight line from \((0,2)\) to \((1,1)\). b. \(C\) is the parabolic curve \(y=x^{2}\) from \((0,0)\) to \((2,4)\). c. \(C\) is the circular path from \((1,0)\) to \((0,1)\) in a clockwise direction.

Let \(S\) be a closed surface and \(V\) the enclosed volume. Prove Green's first and second identities, respectively. a. \(\int_{S} \phi \nabla \psi \cdot \mathbf{n} d S=\int_{V}\left(\phi \nabla^{2} \psi+\nabla \phi \cdot \nabla \psi\right) d V\). b. \(\int_{S}[\phi \nabla \psi-\psi \nabla \phi] \cdot \mathbf{n} d S=\int_{V}\left(\phi \nabla^{2} \psi-\psi \nabla^{2} \phi\right) d V\).

The moments of inertia for a system of point masses are given by sums instead of integrals. For example, \(I_{x x}=\sum_{i} m_{i}\left(y_{i}^{2}+z_{i}^{2}\right)\) and \(I_{x y}=\) \(-\sum_{i} m_{i} x_{i} y_{i}\). Find the inertia tensor about the origin for \(m_{1}=2.0 \mathrm{~kg}\) at \((1.0,0,1.0), m_{2}=5.0 \mathrm{~kg}\) at \((1.0,-1.0,0)\), and \(m_{3}=1.0 \mathrm{~kg}\) at \((1.0,1.0,1.0)\) where the coordinate units are in meters.

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