Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Find the principal value of \(i^{i}\). Rewrite the base, \(i\), as an exponential first.

Short Answer

Expert verified
\(i^{i}\) is equal to \(e^{-\frac{\pi}{2}}\) or approximately 0.20788 when calculated to 5 decimal places.

Step by step solution

01

Represent \(i\) in polar form

We know that \(i\) is equal to \(e^{\frac{\pi}{2}i}\) when represented in polar form. This is because \(i\) lies on the imaginary axis and the argument (the angle it makes with the positive real axis, measured in the counter-clockwise direction) is \(\frac{\pi}{2}\) (or 90 degrees).
02

Substitute \(i\) with its Exponential Equivalent in the Expression \(i^{i}\)

Replace \(i\) with \(e^{\frac{\pi}{2}i}\) in the equation \(i^{i}\). This gives us \((e^{\frac{\pi}{2}i})^{i}\). Then using the power rule of exponents, we get \(e^{-\frac{\pi}{2}}\).
03

Evaluate the expression

We evaluate \(e^{-\frac{\pi}{2}}\). This is done by calculating the value using the exponential function in a calculator and rounding to some decimal places or by leaving it as is. The principal value is found to be approximately 0.20788, but the principal value in terms of \(e\) is more exact and would be \(e^{-\frac{\pi}{2}}\)

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Exponentiation of Complex Numbers
The concept of exponentiation involves raising a number to a power. When dealing with complex numbers, this requires some adjustments.
To find the exponentiation of a complex number like in the exercise, we use polar coordinates. The number is first expressed in exponential form as a base raised to a power which is itself a complex number.
For instance, for the complex number \(i\), we express it as \(e^{i\theta}\), where \(\theta\) represents the angle in the polar form. In the step-by-step solution, this is seen when \(i^i\) is transformed into \((e^{\frac{\pi}{2}i})^i\).
Using exponentiation rules, this translates to \(e^{i\cdot\frac{\pi}{2}i}\), simplifying ultimately to \(e^{-\frac{\pi}{2}}\).
  • This process involves converting the complex base to its exponential form.
  • Then applying properties of exponents to combine powers efficiently.
Polar Form
Polar form is a way of expressing complex numbers. Complex numbers can be split into two components: real and imaginary. In polar notation, these are represented using a magnitude and an angle.
To work with complex exponentiation, converting numbers to polar form is key.
For example, the imaginary unit \(i\) is shown in polar form as \(e^{\frac{\pi}{2}i}\). Here, the angle \(\frac{\pi}{2}\) (or 90 degrees) reflects \(i\)'s position on the complex plane, lying on the imaginary axis.
  • Polar form incorporates both the radius and the angle the number makes with the positive real axis.
  • This facilitates operations like multiplication, division, and exponentiation of complex numbers.
Converting to polar form simplifies the handling of powers and roots, since it transforms the problem into manageable multiplication and addition tasks.
Principal Value
The principal value of a complex number solution is the most commonly accepted one, often seen as the primary angle or result.
In exponential expressions like \(i^i\), achieving the principal value involves evaluating the expression within its main branch of results.
In step 3 of the solution, \(e^{-\frac{\pi}{2}}\) is named the principal value. It is regarded as the primary and simplest result derived from the process.
  • The principal value ensures the complex power solutions are in a standardized form.
  • While there can be multiple results due to periodicity in complex numbers, the principal value is often used for clarity and precision.
This approach aids consistency and reduces ambiguity in complex calculations.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Consider the circle \(|z-1|=1\) a. Rewrite the equation in rectangular coordinates by setting \(z=\) \(x+i y\) b. Sketch the resulting circle using part a. c. Consider the image of the circle under the mapping \(f(z)=z^{2}\), given by \(\left|z^{2}-1\right|=1\) i. By inserting \(z=r e^{i \theta}=r(\cos \theta+i \sin \theta)\), find the equation of the image curve in polar coordinates. ii. Sketch the image curve. You may need to refer to your Calculus. II text for polar plots. [Maple might help.]

Show that \(\sin (x+i y)=\sin x \cosh y+i \cos x \sinh y\) using trigonometric identities and the exponential forms of these functions.

Let \(C\) be the positively oriented ellipse \(3 x^{2}+y^{2}=9\). Define $$ F\left(z_{0}\right)=\int_{C} \frac{z^{2}+2 z}{z-z_{0}} d z $$

Show that $$ \int_{C} \frac{d z}{(z-1-i)^{n+1}}=\left\\{\begin{array}{cl} 0, & n \neq 0 \\ 2 \pi i, & n=0 \end{array}\right. $$ for \(C\) the boundary of the square \(0 \leq x \leq 2,0 \leq y \leq 2\) taken counterclockwise. [Hint: Use the fact that contours can be deformed into simpler shapes (like a circle) as long as the integrand is analytic in the region between them. After picking a simpler contour, integrate using parametrization.].

Evaluate the following integrals: a. \(\int_{C} \bar{z} d z\), where \(C\) is the parabola \(y=x^{2}\) from \(z=0\) to \(z=1+i\). b. \(\int_{C} f(z) d z\), where \(f(z)=2 z-\bar{z}\) and \(C\) is the path from \(z=0\) to \(z=2+i\) consisting of two line segments from \(z=0\) to \(z=2\) and then \(z=2\) to \(z=2+i\) c. \(\int_{C} \frac{1}{x^{2}+4} d z\) for \(C\) the positively oriented circle, \(|z|=2\). [Hint: Parametrize the circle as \(z=2 e^{i \theta}\), multiply numerator and denominator by \(e^{-i \theta}\), and put in trigonometric form.]

See all solutions

Recommended explanations on Combined Science Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free