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A dimeric allosteric protein is isolated. A scientist determines that the value of \(K_{\mathrm{D}}\) for the first binding site is \(25 \mathrm{nM}\) and that the Hill coefficient is 1.6. a. What fraction of the protein has ligand bound at \(10 \mathrm{nM}\) concentration of free ligand? b. A single point mutation abolishes all cooperativity in the protein such that the protein binds its ligand with an apparent \(K_{\mathrm{D}}\) equal to \(25 \mathrm{nM}\). What is the fraction of the protein that has ligand bound at \(10 \mathrm{nM}\) concentration of free ligand?

Short Answer

Expert verified
a. Calculate \(\theta\) using the Hill equation: \(\theta \approx 0.263\). b. Calculate \(\theta\) without cooperativity: \(\theta \approx 0.286\).

Step by step solution

01

Understanding the Problem

A dimeric allosteric protein is studied where cooperativity affects ligand binding. We need to consider the effect of cooperativity (Hill coefficient) and the scenario where cooperativity is abolished.
02

Define Required Concepts

Define and understand the terms and equations involved:- The dissociation constant, \(K_{\mathrm{D}}\), represents the ligand concentration at which half of the protein binding sites are occupied.- The Hill equation, \(\theta = \frac{[L]^n}{K_{\text{D}}^n + [L]^n}\), describes the fraction of ligand-bound protein (\(\theta\)) for cooperative binding where \(n\) is the Hill coefficient.
03

Apply Hill Equation for Cooperativity

Given:- \(K_{\mathrm{D}} = 25\, \mathrm{nM}\)- \(n = 1.6\)- Free ligand concentration, \([L] = 10 \, \mathrm{nM}\)Apply the Hill equation:\[\theta = \frac{[L]^{1.6}}{K_{\mathrm{D}}^{1.6} + [L]^{1.6}} = \frac{10^{1.6}}{25^{1.6} + 10^{1.6}}\]Calculate \(\theta\) for the given values.
04

Calculate Without Cooperativity

After mutation, the protein binds with no cooperativity, such that the binding follows the simple relationship:\[\theta = \frac{[L]}{K_{\mathrm{D}} + [L]}\]Using this with the given values:- \(K_{\mathrm{D}} = 25\, \mathrm{nM}\)- \([L] = 10 \, \mathrm{nM}\)Calculate \(\theta\) using:\[\theta = \frac{10}{25 + 10}\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Dissociation Constant (K_D)
The dissociation constant, denoted as \(K_D\), is a key concept in understanding protein-ligand interactions. It represents the concentration of ligand at which half of the available binding sites on the protein are occupied. This important measure helps us grasp how tightly a ligand binds to a protein. A smaller \(K_D\) value signifies a higher affinity since less ligand is needed to occupy the protein's binding sites halfway.

Keep these points in mind about \(K_D\):
  • Determining \(K_D\) involves measuring the concentration of ligand required for half-maximal binding.
  • It is expressed in units of concentration, often as nanomoles (nM) or micromoles (µM).
  • Understanding \(K_D\) helps in evaluating how a drug or signaling molecule might perform under physiological conditions.
Grasping the concept of the dissociation constant is crucial for anyone studying pharmacology or biochemistry, as it plays a significant role in drug development and molecular biology.
Hill Coefficient
The Hill coefficient, symbolized by \(n\), quantifies the degree of cooperativity in ligand binding to a protein. Unlike \(K_D\), which describes binding affinity, the Hill coefficient illustrates how ligand binding at one site of a protein affects binding at another. A Hill coefficient of exactly 1 indicates independent binding, meaning no cooperativity.

Here are some key points about the Hill coefficient:
  • A value of \(n > 1\) indicates positive cooperativity, where binding of one ligand enhances binding of additional ligands.
  • A value of \(n < 1\) suggests negative cooperativity, where binding of one ligand hinders the binding of others.
  • It's a crucial factor in understanding complex protein behaviors, such as those involved in metabolic regulation.
The Hill coefficient is an essential tool for analyzing the dynamic interactions at play within multi-subunit proteins, offering insight into how cellular responses are fine-tuned.
Allosteric Regulation
Allosteric regulation is a mechanism by which proteins can be regulated through conformational changes. It involves molecules (often ligands or interactors) binding to a site on the protein distinct from the active site, known as the allosteric site.

Key aspects of allosteric regulation include:
  • Binding at the allosteric site can induce a change in protein shape, thus influencing the protein's activity.
  • This process can either enhance (allosteric activation) or inhibit (allosteric inhibition) the protein's function.
  • It plays a vital role in cellular signaling and metabolism, allowing for fine control over complex protein networks.
Understanding allosteric regulation is central to appreciating how cells maintain homeostasis and respond flexibly to changes in their environment. It provides excellent targets for drug development, aiming to modulate protein function precisely.
Cooperativity in Proteins
Cooperativity in proteins refers to how the binding of a ligand to one site on a protein affects the binding at another site. It is a hallmark of allosteric proteins, which often consist of multiple subunits. This phenomenon can significantly impact how biological processes are regulated.

Consider these points regarding cooperativity:
  • It explains why some proteins can serve as efficient sensors or switches in signaling pathways.
  • Positive cooperativity is commonly found in hemoglobin, where binding of oxygen to one subunit increases oxygen affinity of the other subunits.
  • It allows for a more precise and sensitive response to changes in ligand concentration.
Cooperativity is a key concept that enhances our understanding of protein function beyond simple binding kinetics, often accounting for the complex behaviors exhibited by enzymes and receptors in living organisms.

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Most popular questions from this chapter

The first and second binding sites of a positively cooperative allosteric dimeric protein have \(K_{\mathrm{D}}\) values of \(100 \mathrm{mM}\) and \(10 \mu \mathrm{M}\), respectively. a. Sketch the binding isotherms as \(\log [f /(1-f)]\) versus \(\log ([\mathrm{L}])\). b. What is the value of the Hill coefficient?

Two homologs of a protein are isolated. Homolog A is a monomer that binds glucose with a \(K_{\mathrm{D}}\) of \(4 \mathrm{mM}\). Homolog B is a positively cooperative dimer. The \(K_{\mathrm{D}}\) of the first binding site of homolog B is measured at \(4 \mathrm{mM}\). At \(1 \mathrm{mM}\) concentration of glucose, it is found that homolog B binds twice as much glucose as homolog A. What is the Hill coefficient of homolog B?

The transcription of a gene is controlled by a transcription factor binding either glucose or lactose. When there is \(0.2 \mathrm{mM}\) of either glucose or lactose in the cell, the gene is transcribed at about \(10 \%\) of the maximum. When there is more than \(2 \mathrm{mM}\) glucose in the cell, the gene is fully induced. However, when there is \(2 \mathrm{mM}\) lactose in the cell, the amount of transcription is approximately half of the maximum. At \(40 \mathrm{mM}\) of either glucose or lactose in the cell, the gene is fully induced. The transcriptional regulation is likely: a. Ultrasensitive with respect to both glucose and lactose. b. Ultrasensitive with respect to lactose but not glucose. c. Graded with respect to glucose. d. Ultrasensitive with respect to glucose but not lactose. e. Hyperbolic with respect to glucose but not lactose.

Two proteins are modified by myristoylation, which targets them to the plasma membrane in a cell at \(25^{\circ} \mathrm{C}\). This changes their effective local concentration from 10 \(\mathrm{nM}\) to \(1 \mu \mathrm{M}\). Assume that any favorable mutation would decrease the value of \(\Delta G^{\circ}\) for binding by \(4 \mathrm{~kJ} \cdot \mathrm{mol}^{-1}\). How many favorable mutations would have to occur in the absence of colocalization to result in an equivalent effective affinity as observed when the two proteins are colocalized?

A cyclist is interested in cheating in a race by delivering more oxygen to his muscles. The cyclist reasons that since bisphosphoglycerate (BPG) stabilizes the "T" state of hemoglobin, which reduces its affinity for oxygen, that reducing the BPG concentration in his blood cells should be good for his performance. How might removing BPG have a detrimental effect on the delivery of oxygen to his muscles?

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