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The \(E\). coli lacZYA region will be upregulated if A. there is a defect in binding of the inducer to the product of the Lad gene. B. glucose and lactose are both present, but the cell cannot bind the CAP protein. C. glucose and lactose are both readily available in the growth medium. D. the operator has mutated so it can no longer bind the repressor. E. the Lac corepressor is not present.

Short Answer

Expert verified
Answer: The lacZYA region will be upregulated when the operator has mutated so it can no longer bind the repressor.

Step by step solution

01

Option A

A defect in binding of the inducer to the product of the Lad gene does not result in upregulation of the lacZYA region, as proper inducer binding is necessary for this process.
02

Option B

When glucose and lactose are both present but the cell cannot bind the CAP protein, the lacZYA region won't be upregulated. The CAP protein is required to facilitate transcription when glucose is low, so inability to bind it will prevent upregulation.
03

Option C

The lacZYA region is not upregulated when both glucose and lactose are readily available in the growth medium. The presence of glucose triggers the catabolite repression, inhibiting the transcription of the lac operon even when lactose is present.
04

Option D

When the operator has mutated so it can no longer bind the repressor, the lacZYA region will be upregulated. Lack of binding of the repressor to the operator allows the RNA polymerase to initiate transcription, leading to upregulation.
05

Option E

The absence of the Lac corepressor does not upregulate the lacZYA region by itself, as the presence or absence of glucose and lactose also plays an important role in regulation. Based on this analysis, the correct answer is: D. The operator has mutated so it can no longer bind the repressor.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Catabolite Repression
Catabolite repression is a regulatory mechanism by which the presence of a preferred energy source, such as glucose, suppresses the expression of genes involved in the metabolism of alternative energy sources, like lactose in the case of the lac operon in Escherichia coli (E. coli). This process ensures that the bacterial cell uses the most efficient energy source available.

When glucose is present, the levels of cyclic AMP (cAMP) in the cell are low. This low level of cAMP affects the binding of the catabolite activator protein (CAP) to the promoter region of genes such as those in the lac operon. CAP requires cAMP to bind DNA effectively; without this complex, RNA polymerase is less likely to bind to the promoter, thus decreasing transcription of lac operon genes. This efficient use of resources is particularly important in prokaryotes like E. coli, where energy conservation can be crucial for survival.

Therefore, when glucose is abundant in the growth medium, even if lactose is also present, catabolite repression inhibits the expression of the lac operon genes, avoiding unnecessary production of enzymes that metabolize lactose.
Gene Expression in Prokaryotes
Understanding gene expression in prokaryotes is fundamental in molecular biology. Prokaryotes, such as bacteria, do not have a nucleus to separate transcription and translation processes. Instead, these organisms often regulate gene expression at the transcriptional level via operons.

An operon is a cluster of genes under the control of a single promoter and is typically involved in a common metabolic pathway. The lac operon in E. coli is a prime example of how gene expression can be regulated. When lactose is present and glucose is absent or scarce, the lac operon is activated to produce enzymes needed for the breakdown of lactose. The process is regulated by proteins that can either enhance (activators) or inhibit (repressors) the binding of RNA polymerase to the operon's promoter.

In the case of the lac operon, the regulatory system involves both an activator, the catabolite activator protein (CAP), and a repressor protein. The CAP, when bound with cAMP, enhances transcription, while the lac repressor, when bound with lactose, allows transcription. This system provides a responsive and efficient method of gene expression based on the cell's environmental conditions.
Repressor Protein Function
Repressor proteins are pivotal in the control of gene expression. A repressor binds to specific DNA sequences known as operators, which are located near the promoters of target genes. In doing so, repressors can block the binding of RNA polymerase to the promoter, thereby preventing the initiation of transcription and subsequent gene expression.

In the context of the lac operon, the lac repressor protein binds to the operator in the absence of lactose, effectively shutting down the operon. When lactose is present, it serves as an inducer by binding to the repressor, causing a conformational change that prevents the repressor from binding to the operator. This release allows RNA polymerase access to the promoter, leading to the transcription of the lacZYA genes, which are necessary for lactose metabolism.

However, mutations in the operator sequence can prevent repressor binding, resulting in the lac operon being perpetually active, regardless of lactose presence. As mentioned in our exercise, such a mutation would lead to the upregulation of the lacZYA region, underscoring the significant role repressor proteins play in bacterial gene regulation.

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Most popular questions from this chapter

In eukaryotic transcription by RNA polymerase II, formation of a preinitiation complex A. begins with the binding of a protein (TBP) to the TATA box of the promoter. B. involves the ordered addition of several transcription factors and the RNA polymerase. C. allows an ATP-dependent opening of the two strands of DNA. D. requires that the C-terminal domain of RNA polymerase II not be phosphorylated. E. all of the above.

The problem of pathogenic bacteria becoming resistant to a large number of antibiotics is a serious public health concern. A bacterial strain in a paticnt being treated with one antibiotic may suddenly become resistant not only to that antibiotic but to others as well even though it has not been exposed to the other antibiotics. This occurs when the bacteria acquire a plasmid from another strain that contains several different transposons. In the operation of transposons, A. ryplcally the transposon moves from its original site and relocares to a different site. B. a duplicated transposon must be inserted into the same DNA molecule as the original. C. all transposons are approximately the same size. D. the insertion sites must be in a consensus sequence. E. the transposase may recognize the repetitive ends of the transposon and participate in the cleavage of the recipient site.

All of the following describe an operon except A. it is a control mechanism for eukaryotic genes. B. it includes structural genes. C. it is expected to code for polycistronic mRNA. D. it contains control sequences such as an operator. E. it can have multiple promoters.

In an operon, A. cach gene of the operon is regulated independently. B. control may be exerted via induction or via repression. C. operator and promoter may be trans to the genes they regulate. D. the structural genes are either not expressed ar all or fully expressed. E. control of gene expression consists exclusively of induction and repression.

Since the initiation of eukaryotic transcription involves the interaction of a multitude of transcription factors, there must be regulation of these. Estrogen normally binds to its nuclear receptor and the complex binds to the sterol response element to regulate transcription. Tamoxifen, a drug used to treat breast cancer, competes for the estrogen receptor and reduces transcription of the genes it regulates. Another type of alteration is seen in Holt-Oram syndrome in which there is a mutation in a gene for a transcription factor \((\mathrm{Tbx}),\) leading to defects in formation of the heart. Transcription factors are frequently sequence-specific binding proteins and most likely have one of several specific structural motifs. The helix-turn- helix motif A. coordinates zinc between cysteines and histidines. B. joins two proteins via hydrophobic interactions between leucines. C. forms dimers held together by interaction of a helix on each monomer. D. has one helix that recognizes and binds in the major groove of DNA while hydrophobic interactions with a second helix stabilizes the structure. E. is the only motif that binds in the major groove of DNA.

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