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Fragile \(X\) syndrome is a common form of inherited mental retardation. The mutation in the disease allows the increase of a CGG repeat in a particular gene from a normal of about 30 repeats to \(200-1000\) repeats. This repeat is normally found in the \(5^{\prime}\) untranslated region of a gene for the protein FMR1. FMR1 might be involved in the translation of brain-specific mRNAs during brain development. The consequence of the very large number of \(C G G\) repeats in the DNA is extensive methylation of the entire promoter region of the FMR1 gene. Methylation of bases in DNA usually A. facilitates the binding of transcription factors to the DNA. B. makes a difference in activity only if it occurs in an enhancer region. C. prevents chromatin from unwinding. D. inactivates DNA for transcription. E. results in increased production of the product of whatever gene is methylated.

Short Answer

Expert verified
Answer: Inactivates DNA for transcription.

Step by step solution

01

Understanding DNA methylation

First, let's understand what DNA methylation is. DNA methylation is a process that involves the addition of a methyl group to the Cytosine base in the DNA. This process plays a crucial role in controlling gene expression, and it can either activate or repress the transcription of specific genes.
02

Analyze the given options

Now that we have a basic understanding of DNA methylation, let's examine each option: A. Facilitates the binding of transcription factors to the DNA: Methylation can sometimes block the binding of transcription factors, which represses gene transcription. B. Makes a difference in activity only if it occurs in an enhancer region: This statement is incorrect because methylation can affect gene activity regardless of its location in the DNA. C. Prevents chromatin from unwinding: Methylation can lead to a more compact chromatin structure, which can prevent the chromatin from unwinding and make it less accessible to the transcription machinery. D. Inactivates DNA for transcription: Methylation can repress gene transcription by preventing the binding of transcription factors or making chromatin less accessible. E. Results in increased production of the product of whatever gene is methylated: Methylation can repress gene transcription, resulting in decreased expression of the gene's product.
03

Select the correct option

Based on the analysis of the given options, the correct answer is: D. Inactivates DNA for transcription. As the extensive methylation of the promoter region of the FMR1 gene leads to inactivation of DNA for transcription, which results in reduced expression of the gene's product.

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Most popular questions from this chapter

How does nonsense-mediated decay help prevent the export and translation of mRNA that would lead to a shorter, nonfunctional protein?

Processing of transfer RNA (tRNA) A. involves cleaving out several different tRNAs from one primary transcript. B. involves only exonucleases. C. cleaves excess bases from the \(3^{\prime}\) -end after the sequence CCA. D. cleaves excess bases from either end of the primary transcript but not in the interior of the molecule. E. necessitates modification of some of the bases by methylation.

Termination of a prokaryotic transcript A. is a random process. B. requires the presence of the rho subunit of the holoenzyme. C. does not require rho factor if the end of the gene contains a G-C rich palindrome. D. is most efficient if there is an A-T-rich segment at the end of the gene. E. requires an ATPase in addition to rho factor.

The synthesis of normal adult hemoglobin (HbA) requires the coordinated synthesis \(\alpha\) -globin and \(\beta\) -globin. \(\beta\) -Thalassemia is a genetic disease leading to a deficiency of \(\beta\) -globin chains and an inability of the blood to deliver oxygen properly. \(\beta\) -Thalassernia can result from a wide variety of mutations. One mutation leading to \(\beta\) -thalassemia occurs at a splice junction. Which of the following statements about removing introns is correct? A. Small nuclear ribonucleoproteins (snRNP) are necessary for removing introns. B. The consensus sequences at the \(5^{\prime}-\) and \(3^{\prime}\) -ends of introns are identical. C. Removal of an intron does not require metabolic energy. D. The exon at one end of an intron must always be joined to the exon at its other end. E. The nucleoside at the end of the intron first released forms a bond with a \(3^{\prime}\) -OH group on one of the nucleotides within the intron.

Protooncogenes produce products that have specific roles in regulating growth and differentiation of normal cells. Mutations can turn these genes into oncogenes whose products are less responsive to normal control. Unmutated protein \(\mathrm{p} 53,\) a tumor suppressor, is a transcription factor, inhibiting some genes and activating others. P53 inhibits genes with TATA sequences and activates genes for DNA repair. The TATA sequence A. occurs about 25 bp downstream from the start of transcription. B. binds directly to RNA polymerase. C. binds transcription factors which bind RNA polymerase. D. binds p53. E. is an enhancer sequence.

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