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The sigma \((\sigma)\) subunit of prokaryotic RNA polymerase A. is part of the core enzyme. B. binds the antibiotic rifampicin. C. is inhibited by \(\alpha\) -amanitin. D. must be present for transcription to occur. E. specifically recognizes promoter sites.

Short Answer

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A. It is part of the core enzyme. B. Rifampicin binds to it and inhibits its function. C. α-amanitin is an inhibitor of its activity. D. It must be present for transcription to occur. E. Its specificity is determined only by its amino acid sequence. Answer: D. It must be present for transcription to occur.

Step by step solution

01

Understand RNA Polymerase

RNA polymerase is the enzyme responsible for synthesizing RNA from a DNA template; in prokaryotes, it consists of a core enzyme and a sigma factor. The core enzyme is responsible for RNA synthesis, whereas the sigma factor helps in recognizing promoter sequences on the DNA.
02

Define the Role of Sigma Subunit

The sigma subunit of prokaryotic RNA polymerase is a separate protein that associates with the core enzyme. It helps the RNA polymerase enzyme recognize specific promoter sites on the DNA and initiate transcription.
03

Compare Sigma Subunit Properties to Options

A. The sigma subunit is not part of the core enzyme but instead binds to it for promoter recognition. B. Rifampicin binds to the core RNA polymerase enzyme, not the sigma subunit. C. \(\alpha\)-amanitin is an inhibitor of eukaryotic RNA polymerase, not prokaryotic RNA polymerase. D. The sigma subunit is necessary for transcription initiation as it recognizes promoter sequences on DNA. This statement is correct. E. While the sigma subunit is indeed responsible for promoter recognition, its specificity is influenced by the promoter sequences and additional transcription factors.
04

Conclusion

Among the options provided, option D (the sigma subunit must be present for transcription to occur) is the correct property regarding the sigma subunit of prokaryotic RNA polymerase.

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Most popular questions from this chapter

In the cellular turnover of RNA, A. repair is more active than degradation. B. regions of extensive base pairing are more susceptible to cleavage. C. a small double-stranded region of mRNA could lead to cleavage of the mRNA if one strand has perfect complementarity with a region of the mRNA. D. the products are always nucleotides with a phosphate at the \(5^{\prime}-\mathrm{OH}\) group. E. all species except rRNA are cleaved.

Eukaryotic transcription A. is independent of the presence of upstream consensus sequences. B. may involve a promoter located within the region transcribed rather than upstream. C. requires a separate promoter region for each of the three ribosomal RNAs transcribed. D. requires that the entire gene be in the nucleosome form of chromatin. E. is affected by enhancer sequences only if they are adjacent to the promoter.

a. How could you experimentally determine whether a purified preparation of an RNA polymerase is from a prokaryotic or eukaryotic source? b. A purified preparation of RNA polymerase is sensitive to inhibition by \(\alpha\) -amanitin at a concentration of \(10^{-8} \mathrm{M}\). The synthesis of what type or types of RNA is inhibited?

In eukaryotic transcription, A. RNA polymerase does not require a template. B. all RNA is synthesized in the nucleolus. C. consensus sequences are the only known promoter elements. D. phosphodiester bond formation is favored because there is pyrophosphate hydrolysis. E. RNA polymerase requires a primer.

Processing of transfer RNA (tRNA) A. involves cleaving out several different tRNAs from one primary transcript. B. involves only exonucleases. C. cleaves excess bases from the \(3^{\prime}\) -end after the sequence CCA. D. cleaves excess bases from either end of the primary transcript but not in the interior of the molecule. E. necessitates modification of some of the bases by methylation.

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