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Protooncogenes produce products that have specific roles in regulating growth and differentiation of normal cells. Mutations can turn these genes into oncogenes whose products are less responsive to normal control. Unmutated protein \(\mathrm{p} 53,\) a tumor suppressor, is a transcription factor, inhibiting some genes and activating others. P53 inhibits genes with TATA sequences and activates genes for DNA repair. The TATA sequence A. occurs about 25 bp downstream from the start of transcription. B. binds directly to RNA polymerase. C. binds transcription factors which bind RNA polymerase. D. binds p53. E. is an enhancer sequence.

Short Answer

Expert verified
Answer: The TATA sequence binds transcription factors which bind RNA polymerase.

Step by step solution

01

Understand the roles of p53 and transcription factors.

The p53 tumor suppressor protein is a transcription factor that inhibits some genes and activates others. Transcription factors, including p53, are proteins that help control the expression of other genes by binding to specific sequences on DNA.
02

Analyze the given options.

Let us go through each option and analyze them to find the correct answer: A. The TATA sequence occurs about 25 bp downstream from the start of transcription. - Incorrect. The TATA sequence occurs about 25 to 30 bp upstream of the transcription initiation site. B. The TATA sequence binds directly to RNA polymerase. - Incorrect. The TATA sequence does not directly bind to RNA polymerase. C. The TATA sequence binds transcription factors which bind RNA polymerase. - Correct. The TATA sequence binds transcription factors like TATA-binding protein (TBP), which in turn recruits RNA polymerase. D. The TATA sequence binds p53. - Incorrect. p53 acts as a transcription factor, but it does not directly bind to the TATA sequence. It generally binds to different consensus sequences on the target genes. E. The TATA sequence is an enhancer sequence. - Incorrect. The TATA sequence is not an enhancer sequence but rather a promoter element, playing a role in the initiation of transcription.
03

Choose the correct answer.

The correct answer is option C: The TATA sequence binds transcription factors which bind RNA polymerase.

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Most popular questions from this chapter

In eukaryotic transcription, A. RNA polymerase does not require a template. B. all RNA is synthesized in the nucleolus. C. consensus sequences are the only known promoter elements. D. phosphodiester bond formation is favored because there is pyrophosphate hydrolysis. E. RNA polymerase requires a primer.

Processing of transfer RNA (tRNA) A. involves cleaving out several different tRNAs from one primary transcript. B. involves only exonucleases. C. cleaves excess bases from the \(3^{\prime}\) -end after the sequence CCA. D. cleaves excess bases from either end of the primary transcript but not in the interior of the molecule. E. necessitates modification of some of the bases by methylation.

The sigma \((\sigma)\) subunit of prokaryotic RNA polymerase A. is part of the core enzyme. B. binds the antibiotic rifampicin. C. is inhibited by \(\alpha\) -amanitin. D. must be present for transcription to occur. E. specifically recognizes promoter sites.

a. How could you experimentally determine whether a purified preparation of an RNA polymerase is from a prokaryotic or eukaryotic source? b. A purified preparation of RNA polymerase is sensitive to inhibition by \(\alpha\) -amanitin at a concentration of \(10^{-8} \mathrm{M}\). The synthesis of what type or types of RNA is inhibited?

In the cellular turnover of RNA, A. repair is more active than degradation. B. regions of extensive base pairing are more susceptible to cleavage. C. a small double-stranded region of mRNA could lead to cleavage of the mRNA if one strand has perfect complementarity with a region of the mRNA. D. the products are always nucleotides with a phosphate at the \(5^{\prime}-\mathrm{OH}\) group. E. all species except rRNA are cleaved.

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