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The synthesis of normal adult hemoglobin (HbA) requires the coordinated synthesis \(\alpha\) -globin and \(\beta\) -globin. \(\beta\) -Thalassemia is a genetic disease leading to a deficiency of \(\beta\) -globin chains and an inability of the blood to deliver oxygen properly. \(\beta\) -Thalassernia can result from a wide variety of mutations. One mutation leading to \(\beta\) -thalassemia occurs at a splice junction. Which of the following statements about removing introns is correct? A. Small nuclear ribonucleoproteins (snRNP) are necessary for removing introns. B. The consensus sequences at the \(5^{\prime}-\) and \(3^{\prime}\) -ends of introns are identical. C. Removal of an intron does not require metabolic energy. D. The exon at one end of an intron must always be joined to the exon at its other end. E. The nucleoside at the end of the intron first released forms a bond with a \(3^{\prime}\) -OH group on one of the nucleotides within the intron.

Short Answer

Expert verified
Answer: A. snRNP are necessary for removing introns.

Step by step solution

01

A. snRNP are necessary for removing introns

This statement is correct. Small nuclear ribonucleoproteins (snRNP) are part of the spliceosome complex which is responsible for removing introns from the pre-mRNA during the splicing process. The snRNPs bind to specific sequences on the pre-mRNA to perform their action.
02

B. Consensus sequences at the ends of introns are identical

This statement is incorrect. The consensus sequences at the \(5'\) and \(3'\) ends of introns are not identical. The \(5'\) splice site has the consensus sequence GU, while the \(3'\) splice site has the consensus sequence AG.
03

C. No metabolic energy is required to remove an intron

This statement is incorrect. Energy in the form of ATP or GTP is required for the proper functioning of the spliceosome, which is responsible for removing introns and joining exons together.
04

D. The exon at one end of an intron must always be joined to the exon at its other end

This statement is incorrect. The exon at one end of an intron can be joined to another exon in alternative splicing, which allows for the synthesis of multiple different proteins from a single pre-mRNA.
05

E. The nucleoside at the end of the intron forms a bond with a \(3'\) -OH group on one of the nucleotides within the intron

This statement is incorrect. In the intron removal process, the \(2'\) -OH group of a branch-point adenosine within the intron attacks the \(5'\) splice site, forming a lariat structure. The \(3'\) -OH group of the upstream exon is then free to attack the \(3'\) splice site, releasing the intron lariat and joining the exons together. The correct statement is A. Small nuclear ribonucleoproteins (snRNP) are necessary for removing introns.

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Most popular questions from this chapter

In eukaryotic transcription, A. RNA polymerase does not require a template. B. all RNA is synthesized in the nucleolus. C. consensus sequences are the only known promoter elements. D. phosphodiester bond formation is favored because there is pyrophosphate hydrolysis. E. RNA polymerase requires a primer.

Fragile \(X\) syndrome is a common form of inherited mental retardation. The mutation in the disease allows the increase of a CGG repeat in a particular gene from a normal of about 30 repeats to \(200-1000\) repeats. This repeat is normally found in the \(5^{\prime}\) untranslated region of a gene for the protein FMR1. FMR1 might be involved in the translation of brain-specific mRNAs during brain development. The consequence of the very large number of \(C G G\) repeats in the DNA is extensive methylation of the entire promoter region of the FMR1 gene. Methylation of bases in DNA usually A. facilitates the binding of transcription factors to the DNA. B. makes a difference in activity only if it occurs in an enhancer region. C. prevents chromatin from unwinding. D. inactivates DNA for transcription. E. results in increased production of the product of whatever gene is methylated.

Protooncogenes produce products that have specific roles in regulating growth and differentiation of normal cells. Mutations can turn these genes into oncogenes whose products are less responsive to normal control. Unmutated protein \(\mathrm{p} 53,\) a tumor suppressor, is a transcription factor, inhibiting some genes and activating others. P53 inhibits genes with TATA sequences and activates genes for DNA repair. The TATA sequence A. occurs about 25 bp downstream from the start of transcription. B. binds directly to RNA polymerase. C. binds transcription factors which bind RNA polymerase. D. binds p53. E. is an enhancer sequence.

Eukaryotic transcription A. is independent of the presence of upstream consensus sequences. B. may involve a promoter located within the region transcribed rather than upstream. C. requires a separate promoter region for each of the three ribosomal RNAs transcribed. D. requires that the entire gene be in the nucleosome form of chromatin. E. is affected by enhancer sequences only if they are adjacent to the promoter.

a. How could you experimentally determine whether a purified preparation of an RNA polymerase is from a prokaryotic or eukaryotic source? b. A purified preparation of RNA polymerase is sensitive to inhibition by \(\alpha\) -amanitin at a concentration of \(10^{-8} \mathrm{M}\). The synthesis of what type or types of RNA is inhibited?

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