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In the coding strand of DNA for the alpha gene of normal hemoglobin \((\mathrm{HbA}),\) the three bases that correspond to codon 142 of the mRNA are TAA and the alpha chain has 141 amino acids. In the coding strand of the gene for the alpha chain of Hemoglobin Constant Spring, the three bases are CAA and the chain contains 172 amino acids. Explain the mutation that has occurred.

Short Answer

Expert verified
Answer: The specific mutation in Hemoglobin Constant Spring changed the 142nd codon in the DNA coding strand from TAA (a stop codon) to CAA (which codes for the amino acid glutamine). This mutation leads to an elongated alpha chain, containing 172 amino acids instead of the normal 141 amino acids found in HbA.

Step by step solution

01

Understand the role of DNA, mRNA, and amino acids

DNA contains the genetic information for creating proteins, which are made up of amino acids. The process of turning this genetic information into proteins involves two main steps: transcription, where DNA is transformed into mRNA, and translation, where mRNA is transformed into the amino acid sequence. The mRNA carries the information from the DNA in the form of three-letter sequences called codons, which code for specific amino acids during translation.
02

Compare the codons between normal hemoglobin and Hemoglobin Constant Spring

For normal hemoglobin (HbA), the 142nd mRNA codon is derived from the DNA coding strand with bases TAA. In Hemoglobin Constant Spring, the three bases in the coding strand at the same position are CAA. This change represents a point mutation in the DNA coding strand.
03

Identify the change in amino acids

The normal hemoglobin (HbA) contains 141 amino acids in its alpha chain, while the Hemoglobin Constant Spring contains 172 amino acids. There is an increase of 31 amino acids in the alpha chain of Hemoglobin Constant Spring compared to HbA.
04

Determine the specific mutation

The change in the DNA coding strand from TAA to CAA for the 142nd codon leads to different mRNA codon and might affect amino acid coding. In this case, the mutation from TAA to CAA has caused a change from a stop codon, which signals the end of translation, to a codon that codes for an amino acid (glutamine). Since the mutation has changed a stop codon to a coding codon, the translation process does not stop at the 141st amino acid as it does in normal HbA, but continues, ultimately forming a longer alpha chain with 172 amino acids.
05

Conclusion

The mutation that occurred in Hemoglobin Constant Spring has changed the 142nd codon in the DNA coding strand from TAA (which is a stop codon) to CAA (which codes for the amino acid glutamine). As a result, the alpha chain of Hemoglobin Constant Spring has been elongated, containing 172 amino acids instead of the normal 141 amino acids found in HbA.

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Most popular questions from this chapter

Retroviruses, like HIV which causes AIDS, have their genetic information in the form of RNA. Reverse transcriptase synthesizes a DNA copy of the viral genome. One drug used in treating AIDS is AZT, an analog of deoxythymidine, which has an azido group at the \(3^{\prime}\) position of the sugar. It can be phosphorylated and competes with dTTP for incorporation into the reverse transcript. Once incorporated, its presence terminates chain elongation. There is a window in which the effect is primarily on viral replication since AZT is much less effective at competing with dTTP for incorporation by cellular DNA polymerases because of the proofreading ability of DNA polymerases. Proofreading activity to maintain the fidelity of DNA synthesis A. occurs after the synthesis has been completed. B. is a function of \(3^{\prime}\) to \(5^{\prime}\) exonuclease activity intrinsic to or associated with DNA polymerases. C. requires the presence of an enzyme separate from the DNA polymerases. D. removes mismatched bases in the interior of the chain. E. does not occur in prokaryotes.

Interfering with topoisomerases is one way of inhibiting DNA replication. Certain antibiotics target DNA gyrase (type II topoisomerase) of \(E\) coli inhibiting catalytic activity. Topoisomerase poisons prevent resealing of the phosphodiester bond, leaving covalent protein-DNA junctions. These compounds are used in rreating infections and as chemotherapeutic agentsAll of the following are correct about double-strand breaks in DNA except they A. can lead to loss of genetic information. B. are always involved in homologous recombination. C. are involved in nonhomologous recombination. D. are associated with a heterodimer (Ku) in mammals. E. can lead to mutations or improper regulation of gene expression.

Retroviruses, like HIV which causes AIDS, have their genetic information in the form of RNA. Reverse transcriptase synthesizes a DNA copy of the viral genome. One drug used in treating AIDS is AZT, an analog of deoxythymidine, which has an azido group at the \(3^{\prime}\) position of the sugar. It can be phosphorylated and competes with dTTP for incorporation into the reverse transcript. Once incorporated, its presence terminates chain elongation. The growing chain is terminated becausc A. the analog can not hydrogen bond to RNA. B. the presence of the AZT analog inhibits the proofreading ability of reverse transcriptase. C. AZT does not have a free \(3^{\prime}\) - \(\mathrm{OH}\). D. the analog causes distortion of the growing chain, inhibiting reverse transcriptase. E. \(d T T P\) can no longer be added to the growing chain.

Patients with the rare genetic disease xeroderma pigmentosum (XP) are very sensitive to light and are highly susceptible to skin cancers. The study of such patients has enhanced our knowledge of DNA repair because \(X P\) is caused by defective DNA repairnucleotide excision repair. (A variant, XP-V, is deficient in postreplication repair.) In nucleotide excision repair A. removal of the damaged bases occurs on only one strand of the DNA. B. only thymine dimers generated by UV light can be removed. C. the excision nuclease is an exonuclease. D. a single multifunctional enzyme carries out the repair process. E. only the damaged nucleotides are removed.

Mismatch repair removes replication errors by excising incorrect bases. There is no DNA damage or modified bases present. How does the cell distinguish the newly synthesized strand and preserve the correct parental DNA strand?

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