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Patients with hereditary fructose intolerance are deficient in the liver form of the enzyme aldolase. Consumption of fructose leads to a depletion of ATP and \(P\), in the liver, which, in turn, leads to cell damage, Much of the cell damage can be attributed to the inability to maintain normal ion gradients by ATP-dependent pumps. The first step in liver's metabolism of fructose is A. isomerization to glucose. B. phosphorylation to fructose 1,6 -bisphosphate by ATP. C. phosphorylation to fructose 1-phosphate by ATP. D. phosphorylation to fructose 6 -phosphate by ATP. E cleavage by aldolase.

Short Answer

Expert verified
Answer: The first step in liver's metabolism of fructose is phosphorylation to fructose 1-phosphate by ATP.

Step by step solution

01

Understand hereditary fructose intolerance and its effects on aldolase

Hereditary fructose intolerance (HFI) is a genetic disorder that affects a person's ability to metabolize fructose (a sugar) properly, due to a deficiency in the liver enzyme aldolase. This enzyme is involved in breaking down fructose into usable energy. Without this enzyme, fructose cannot be efficiently metabolized, leading to harmful effects on the liver cells.
02

Analyze option A - isomerization to glucose

Isomerization is the process by which one molecule is transformed into another molecule that has the same atoms but in a different arrangement. In this case, option A suggests that fructose is converted to glucose, which is another simple sugar. Although fructose can be converted to glucose through a series of metabolic steps, this is not the first step in fructose metabolism in the liver. So, option A is incorrect.
03

Analyze option B - phosphorylation to fructose 1,6-bisphosphate by ATP

Phosphorylation is the process of adding a phosphate group to a molecule, usually from ATP (adenosine triphosphate). Fructose 1,6-bisphosphate is an intermediate in glycolysis (glucose metabolism) and is not a direct product of fructose phosphorylation. So, option B is incorrect.
04

Analyze option C - phosphorylation to fructose 1-phosphate by ATP

The first step in the liver's metabolism of fructose is the phosphorylation of fructose to fructose 1-phosphate by ATP. In the presence of fructokinase, an enzyme in the liver, ATP donates a phosphate group to fructose resulting in fructose 1-phosphate. So, option C is correct.
05

Analyze options D and E for completeness

Option D suggests that fructose is phosphorylated to fructose 6-phosphate by ATP. This is an intermediate step in glucose metabolism, not the first step in fructose metabolism in the liver. So, option D is incorrect. Option E suggests that fructose is cleaved by aldolase. In the context of HFI, individuals have a deficiency of the aldolase enzyme and are unable to perform this step efficiently. Therefore, this is not the first step in liver fructose metabolism, and option E is also incorrect.
06

Conclusion

The correct answer is option C: The first step in liver's metabolism of fructose is phosphorylation to fructose 1-phosphate by ATP.

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Most popular questions from this chapter

When blood glucagon rises, which of the following hepatic enzyme activities falls? A. Adenyl cyclase B. Protein kinase C. 6 -Phosphofructo- 2 -kinase D. Fructose 1,6 -bisphosphatase E. Hexokinase

Glucose 6 -phosphatase, which is deficient in Von Gierke disease, is necessary for the production of blood glucose from A. liver glycogen. B. fructose. C. amino acid carbon chains. D. lactose. E. all of the above.

Alcohol intoxication can lead to hypoglycemia especially if the alcohol is consumed by an undernourished individual or after strenuous exercise. In both cases the hypoglycemia results from the inhibitory effects of alcohol on hepatic gluconcogenesis and occurs under circumstances of heparic glycogen depletion. Alcohol potentiates the hypoglycemic effect of insulin so diaberics who have self-administered insulin and then consumed alcohol are at increased risk. Alcohol metabolism produces large amounts of NADH which inhibit gluconcogenesis by A. shifting the pyruvate-lactate cquilibrium toward lactate. B. favoring the production of oxaloacetate from malate. C. preventing the movement of phosphocaolpyruvate from the mitochondria to the cytasol. D. inhibiting the electron transport chain. E. inhibiting the malate-aspartate shurtle.

6-Phosphofructo-1-kinase activity can be decreased by all of the following except A. ATP at high concentrations. B. cirrate. \(\mathrm{C}_{1} \mathrm{AMP}\) D. low pH. E. decreased concentration of fructose 2,6 -bisphosphate.

The alanine cycle requires more ATP per glucose molecule formed chan does the Cori cycle. Why is chis?

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