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The active form of pyruvate dehydrogenase is favored by the influence of all of the following on pyruvate dehydrogenase kinase except A. low \(\left[\mathrm{Ca}^{2+}\right]\) B. low acetyl CoA/CoASH. C. high [pyruvate]. D. low NADH/NAD \(^{+}\)

Short Answer

Expert verified
Answer: A low concentration of \(\left[\mathrm{Ca}^{2+}\right]\) does NOT favor the active form of pyruvate dehydrogenase, as it fails to inhibit pyruvate dehydrogenase kinase.

Step by step solution

01

Define the role of pyruvate dehydrogenase kinase

Pyruvate dehydrogenase kinase (PDK) is an enzyme that phosphorylates and inactivates pyruvate dehydrogenase (PDH), a key enzyme in the conversion of pyruvate to acetyl-CoA. The active form of PDH is favored when PDK is inactive.
02

Analyze option A - low \(\left[\mathrm{Ca}^{2+}\right]\)

Calcium ions (\(\mathrm{Ca}^{2+}\)) play a role in activating PDH by inhibiting PDK. When the concentration of calcium ions is low, PDK is not inhibited, and therefore PDH is less active.
03

Analyze option B - low acetyl CoA/CoASH

Acetyl CoA and CoASH are substrates involved in the conversion of pyruvate to acetyl-CoA by PDH. A low ratio of acetyl CoA to CoASH suggests that there is less acetyl CoA available, which reduces the feedback inhibition on PDK. This results in greater PDK activity, which in turn inhibits and thus deactivates PDH.
04

Analyze option C - high [pyruvate]

An increase in pyruvate concentration typically drives the reaction forward, converting pyruvate into acetyl-CoA. This process involves the activity of PDH, so a high concentration of pyruvate would promote PDH's active form by decreasing PDK's activity.
05

Analyze option D - low NADH/NAD \(^{+}\)

A low ratio of NADH/NAD \(^{+}\) indicates a high concentration of NAD \(^{+}\), which is a coenzyme required for the PDH-catalyzed reaction. An increase in NAD \(^{+}\) concentration favors the conversion of pyruvate to acetyl-CoA, promoting the active form of PDH. Consequently, PDK's activity is decreased.
06

Identify the correct answer

From the analyses of options A, B, C, and D, we can conclude that option A is the correct answer. A low concentration of \(\left[\mathrm{Ca}^{2+}\right]\) does NOT favor the active form of pyruvate dehydrogenase, as it fails to inhibit pyruvate dehydrogenase kinase.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Pyruvate Dehydrogenase Kinase
Pyruvate dehydrogenase kinase (PDK) is an essential regulator in our metabolism, acting as a gatekeeper for the flow of carbohydrates into the energy extraction processes of the cell. Its primary role is to phosphorylate and inactivate the pyruvate dehydrogenase complex (PDH), which is vital for converting pyruvate—derived from glucose—into acetyl-CoA, the entry molecule for the citric acid cycle.

When the levels of ATP are high, indicating that the energy demands of the cell are met, PDK is activated. This phosphorylates PDH, switching it off and preventing further conversion of pyruvate into fuel when it isn't needed. This is a prime example of how a cell maintains energy homeostasis.
Enzyme Phosphorylation
Enzyme phosphorylation is a pivotal biochemical process where a phosphate group is added to an enzyme, modifying its structure and function. This addition typically involves the transfer of phosphate from ATP, sort of like adding a molecular toggle switch to the enzyme. In the context of pyruvate dehydrogenase regulation, this phosphorylation serves as an off switch by PDK.

Enzyme activity can be reduced or increased post-phosphorylation, making it a vital point of control. In PDH's case, phosphorylation by PDK inhibits its activity, stopping the flow of carbon into the citric acid cycle, reflecting the cell's intricate system to modulate metabolic pathways quickly in response to energetic needs.
Calcium Ion's Role in Metabolic Enzymes
Calcium ions (Ca^{2+}) are widely recognized for their role in signaling within cells. They influence various metabolic enzymes, including PDH. Ca^{2+} interacts directly with PDH and its associated regulatory enzymes, such as PDK.

At high concentrations, Ca^{2+} inhibit the action of PDK, thereby preventing phosphorylation of PDH. As a result, PDH remains active, and the cell can continue to convert pyruvate into acetyl-CoA for energy production. The presence of Ca^{2+} underscores the relationship between cellular signaling and metabolic regulation, as the cell uses these ions as messengers to quickly adapt to changes in conditions such as muscle contraction or neurotransmitter release.
Metabolic Feedback Inhibition
Metabolic feedback inhibition is a mechanism where downstream products control the activity of upstream processes. It's equivalent to a thermostat in your home that adjusts the heating based on the temperature. For PDH, this means that its activity is tightly governed by the concentrations of its products (like acetyl-CoA and NADH) and substrates (such as NAD⁺ and pyruvate).

When product levels are high, they can bind to enzymes and inhibit their function, preventing the unnecessary buildup of products and wasteful expenditure of resources. Conversely, when substrate levels are high, it can signal the need to accelerate metabolic pathways. This feedback inhibition is a form of the cell's self-regulation, ensuring metabolic balance and efficient use of its energy resources.

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Most popular questions from this chapter

The inner mitochondrial membrane contains a transporter for A. NADH. B. acetyl CoA. C. GTP. D. ATP. E. NADPH.

ATP synthase (also known as complex \(V\) ) consists of two domains, \(F_{1}\) and \(F_{0}\) A. \(\mathrm{F}_{1}\) and \(\mathrm{F}_{\mathrm{o}}\) are both integral membrane protein complexes of the outer membrane. B. \(F_{1}\) domain provides a channel for translocation of protons across the membrane. C. \(F_{1}\) binds ATP but not ADP. D. \(F_{1}\) domain catalyzes the synthesis of ATP. E. Only the \(F_{0}\) domain contains more than one subunit.

A bond may be high energy for any of the following reasons except A. products of its cleavage are more resonance stabilized than the original compound. B. the bond is unusually stable, requiring a large energy input to cleave it. C. electrostatic repulsion is relieved when the bond is cleaved. D. a cleavage product may be unstable, tautomerizing to a more stable form. \(\mathbf{E}\). the bond may be strained.

During the transfer of electrons to \(\mathrm{O}_{2}\) via the mitochondrial electron transport chain, A. the energy released is used to translocate protons across the inner membrane. B. a proton gradient is generated with the matrix now being more positive than the intermembrane space. C. pumping of protons across the membrane occurs each time electrons are moved. D. no charge gradient develops because an OH" moves each time a proton does. E. the energy is used directly in the addition of \(P_{i}\) to ADP to form ATP.

Using pyruvate, labeled with \(^{14} \mathrm{C}\) in its keto group, via the pyruvate dehydrogenase reaction and the TCA cycle, where would the carbon label be at the end of one turn of the TCA cycle? Where would the carbon label be at the end of the second turn of the cycle?

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