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Using pyruvate, labeled with \(^{14} \mathrm{C}\) in its keto group, via the pyruvate dehydrogenase reaction and the TCA cycle, where would the carbon label be at the end of one turn of the TCA cycle? Where would the carbon label be at the end of the second turn of the cycle?

Short Answer

Expert verified
After two turns of the TCA cycle, where is the carbon label (^14C)? Answer: After one turn of the TCA cycle, the ^14C label is at C1 of oxaloacetate. After two turns of the TCA cycle, the ^14C label is released as CO2 and is no longer in the cycle.

Step by step solution

01

Understand the pyruvate dehydrogenase reaction and enter the TCA cycle

Pyruvate first undergoes decarboxylation by the pyruvate dehydrogenase complex to yield Acetyl-CoA, which enters the TCA cycle. In this reaction, the carboxyl carbon (C1) of pyruvate is released as CO2, and the remaining two carbons (C2 and C3) form acetyl-CoA. The \(^{14}\mathrm{C}\) label is in the keto group of pyruvate, which is C2.
02

First turn of the TCA cycle

As Acetyl-CoA enters the TCA cycle, it combines with oxaloacetate (4 carbons) to form citrate (6 carbons). In this reaction, labeled C2 becomes C2 of the resulting citrate molecule. Through the following reactions of the TCA cycle, C2 of citrate maintains its position as C2: 1. Citrate → Isocitrate (via citrate synthase, aconitase enzymes) 2. Isocitrate → α-Ketoglutarate (via isocitrate dehydrogenase enzyme) In the reaction of α-Ketoglutarate → Succinyl-CoA (via α-ketoglutarate dehydrogenase enzyme), carbon C1 of α-Ketoglutarate is released as CO2. Therefore, our labeled carbon (originally C2) is now at position C1 of Succinyl-CoA. During the remaining steps of the TCA cycle, the labeled C1 carbon holds its position as follows: 1. Succinyl-CoA → Succinate 2. Succinate → Fumarate 3. Fumarate → Malate 4. Malate → Oxaloacetate At the end of the first turn of the TCA cycle, our labeled carbon (\(^{14}\mathrm{C}\)) is at C1 in oxaloacetate.
03

Second turn of the TCA cycle

In the second TCA cycle turn, the labeled oxaloacetate (C1 position) combines with another Acetyl-CoA molecule to form citrate. As before, the labeled carbon keeps its position in citrate: 1. Citrate → Isocitrate 2. Isocitrate → α-Ketoglutarate In the α-Ketoglutarate → Succinyl-CoA reaction, the labeled carbon (C1 of α-Ketoglutarate) will be released as CO2. As a result, after the second turn of the TCA cycle, the \(^{14}\mathrm{C}\) label is no longer present in the cycle. In conclusion, at the end of one turn of the TCA cycle, the \(^{14}\mathrm{C}\) label is at C1 of oxaloacetate. At the end of the second turn of the cycle, the \(^{14}\mathrm{C}\) label is released as CO2 and is no longer in the cycle.

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Most popular questions from this chapter

Suppose the specific defect were a mutant pyruvate dehydrogenase (the first catalytic subunit) with poor binding of its prosthetic group. In this type of defect, sometimes greatly increasing the dietary precursor of the prosthetic group is helpful. In this case, increasing which of the following might be helpful? A. Lipoic acid B. Niacin (for NAD) C. Pantothenic acid (for CoA) D. Riboflavin (for FAD) E. Thiamin (for TPP)

The inner mitochondrial membrane contains a transporter for A. NADH. B. acetyl CoA. C. GTP. D. ATP. E. NADPH.

ATP synthase (also known as complex \(V\) ) consists of two domains, \(F_{1}\) and \(F_{0}\) A. \(\mathrm{F}_{1}\) and \(\mathrm{F}_{\mathrm{o}}\) are both integral membrane protein complexes of the outer membrane. B. \(F_{1}\) domain provides a channel for translocation of protons across the membrane. C. \(F_{1}\) binds ATP but not ADP. D. \(F_{1}\) domain catalyzes the synthesis of ATP. E. Only the \(F_{0}\) domain contains more than one subunit.

For the reaction \(A \rightleftharpoons B, \Delta G^{0}=-29.7 \mathrm{kJ} / \mathrm{mol} .\) At \(37^{\circ} \mathrm{C},-2.303\) \(R T=-5.94 \mathrm{kJ} / \mathrm{mol} .\) What is the equilibrium ratio of B/A?

During the transfer of electrons to \(\mathrm{O}_{2}\) via the mitochondrial electron transport chain, A. the energy released is used to translocate protons across the inner membrane. B. a proton gradient is generated with the matrix now being more positive than the intermembrane space. C. pumping of protons across the membrane occurs each time electrons are moved. D. no charge gradient develops because an OH" moves each time a proton does. E. the energy is used directly in the addition of \(P_{i}\) to ADP to form ATP.

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