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Turnover number \(\left(k_{\mathrm{ca}}\right)\) A. is a ratio of the rate constants for the formation of ES and of product. B. has units of 1/time. C. is inversely related to how fast the reaction is. D. for a mutant enzyme can change without any change in the \(K_{m}\) of the reaction. E. has units of substrate concentration.

Short Answer

Expert verified
Based on the analysis of the given statements: Statement A is false. The turnover number (kca) is a measure of enzyme reaction efficiency, not a ratio of rate constants. Statement B is true. The turnover number (kca) has units of 1/time, indicating the number of substrate molecules converted to product molecules per unit time. Statement C is false. The turnover number (kca) is directly related to the reaction rate, not inversely. Statement D is true. The turnover number (kca) and the Michaelis constant (Km) are independent of each other, so a mutant enzyme could potentially change the turnover number without affecting Km. Statement E is false. The turnover number (kca) has units of 1/time, not substrate concentration.

Step by step solution

01

Statement A:

Is a ratio of the rate constants for the formation of ES and of product. This statement is false. The turnover number \((k_{\mathrm{ca}})\), also known as the catalytic rate constant or \(k_{cat}\), is the maximum number of substrate molecules that an enzyme can convert into product molecules per unit time when the enzyme is fully saturated with substrate. It is not a ratio of rate constants but rather a measure of the enzyme reaction efficiency.
02

Statement B:

Has units of 1/time. This statement is true. The turnover number \((k_{\mathrm{ca}})\) is expressed in units of reciprocal time (e.g., s\(^{-1}\) or min\(^{-1}\)), indicating the number of substrate molecules converted to product molecules per unit time when the enzyme is fully saturated.
03

Statement C:

Is inversely related to how fast the reaction is. This statement is false. The turnover number \((k_{\mathrm{ca}})\) is directly related to the reaction rate, not inversely. A higher turnover number indicates that the enzyme converts substrate to product more quickly, whereas a lower turnover number signifies a slower reaction rate.
04

Statement D:

For a mutant enzyme can change without any change in the \(K_{m}\) of the reaction. This statement is true. \(K_{m}\) (the Michaelis constant) and the turnover number \((k_{\mathrm{ca}})\) are independent of each other. A mutant enzyme could potentially change the turnover number without affecting \(K_{m}\), which is a measure of substrate affinity. This suggests that the enzyme's catalytic efficiency may be altered without impacting its affinity for the substrate.
05

Statement E:

Has units of substrate concentration. This statement is false. As mentioned earlier, the turnover number \((k_{\mathrm{ca}})\) has units of 1/time, not substrate concentration. It reflects the maximum reaction rate achieved under saturating substrate conditions and gives information about the enzyme's catalytic efficiency.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Catalytic Rate Constant
In biochemistry, the catalytic rate constant, often symbolized as \(k_{cat}\) or the turnover number, is a critical parameter indicating the rate at which an enzyme can catalyze a reaction. It tells us how many substrate molecules one enzyme molecule can convert into product molecules per second under optimal conditions—that is, when the substrate concentration is so high that all enzyme active sites are always occupied.

When we analyze enzymes, knowing their \(k_{cat}\) provides insight into their efficiency. An enzyme with a higher \(k_{cat}\) can process substrates more quickly, denoting a highly efficient enzyme. In contrast, a lower \(k_{cat}\) implies a less efficient enzyme that catalyzes the reaction at a slower pace. It's essential to understand that the \(k_{cat}\) does not vary with substrate concentration once the enzyme is saturated; hence, its value represents the intrinsic turnover rate of the enzyme itself.
Enzyme Saturation
Enzyme saturation occurs when every active site of the enzyme molecules is occupied by substrate molecules. At this point, increasing the substrate concentration further will not increase the reaction rate because there are no free active sites left for additional substrate molecules to bind to.

At saturation, the reaction rate has reached its maximum, termed the maximum velocity (\(V_{max}\)). The relationship between substrate concentration and reaction rate is hyperbolic and is best described by the Michaelis-Menten equation. Enzyme saturation is essential in enzyme kinetics because it ensures that the measurement of \(k_{cat}\) reflects the enzyme's maximum catalytic capacity without interference from limiting substrate availability.
Michaelis Constant (Km)
The Michaelis constant, denoted as \(K_{m}\), is a measure used to describe the affinity of an enzyme for its substrate. It is defined as the substrate concentration at which the reaction rate is half of the maximum velocity (\(V_{max}\)). A low \(K_{m}\) value implies high substrate affinity, meaning the enzyme can achieve \(V_{max}\) even at low substrate concentrations. Conversely, a high \(K_{m}\) suggests low substrate affinity, in that higher substrate concentrations are necessary to reach \(V_{max}\).

Understanding \(K_{m}\) helps in determining the efficiency of enzymes in their natural physiological context where substrate concentrations may vary. The Michaelis constant is crucial when comparing the behavior of wild-type enzymes to mutant forms, as any alteration in \(K_{m}\) could imply changes in the enzyme's interaction with its substrate.
Reaction Rate
The reaction rate in biochemistry refers to the speed at which a reaction occurs. For enzyme-catalyzed reactions, it's specifically the rate at which the enzyme converts substrate molecules into product molecules. The rate can be influenced by several factors, including enzyme and substrate concentration, temperature, pH, and the presence of inhibitors or activators.

Enzymes catalyze reactions by lowering the activation energy required, which increases the reaction rate. The reaction rate is initially proportional to the substrate concentration but levels off as the enzyme becomes saturated, leading to a plateau—the maximum reaction rate (\(V_{max}\)). Understanding the factors that affect reaction rate is fundamental to controlling and predicting the outcomes of biochemical reactions.
Substrate Affinity
Substrate affinity is a term used to describe how strongly an enzyme binds to its substrate. It's an essential concept because it determines how likely a substrate molecule is to find and occupy the active site of an enzyme. The stronger the affinity, the more likely an enzyme is to be occupied by the substrate and catalyze a reaction, even at low substrate concentrations.

Substrate affinity can be quantitatively expressed through the Michaelis constant (\(K_{m}\)). Enzymes with a low \(K_{m}\) have high affinity, as they can achieve half the maximum reaction rate at lower concentrations of substrate. This relationship between \(K_{m}\) and substrate affinity is vital when considering the effectiveness of enzymes under physiological conditions, where the substrate might not always be abundant.

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Most popular questions from this chapter

An enzyme can facilitate the rate of a reaction by A. stabilizing the transition state. B. binding very tightly to the substrate. C. binding very tightly to the product. D. preventing the substrate from changing its ionic state. E. preventing the reaction from proceeding in the reverse direction.

Gout is a disease in which uric acid is high in blood and urine. One patient who excreted three times normal uric acid had very high blood levels of PRPP, an intermediate in biosynthesis of AMP and GMP, which are precursors of ATP and GTP. Degradation of these products produces uric acid. The patient's PRPP synthetase had normal \(K_{m}\) and \(V_{\max }\) values but was insensitive to regulation by the end products of the pathway (ATP, GTP). These are negative allosteric modifiers of PRPP synthetase. All of the following statements about allosteric effectors are correct except they A. may increase the enzyme's affinity for its substrate. B. may decrease the enzyme's affinity for its substrate. C. bind at the substrate binding site. D. cause a conformational change in the enzyme. E. can change either the \(K_{m}\) or the \(V_{\max }\) of the reaction.

A man of Japanese ancestry found himself to be experiencing severe flushing and a very rapid heart rate after consuming one alcoholic beverage. His companion, a Caucasian male, did not have the same symptoms even though he had finished his second drink. These physiological effects are related to the presence of acetaldehyde \(\left(\mathrm{CH}_{3} \mathrm{CH} \mathrm{O}\right)\) generated from the alcohol. Acetaldehyde is normally removed by the reaction of mitochondrial aldehyde dehydrogenase which catalyzes the reaction $$\mathrm{CH}_{3} \mathrm{CHO}+\mathrm{NAD}^{+} \leftrightharpoons \mathrm{CH}_{3} \mathrm{COO}^{-}+\mathrm{NADH}+\mathrm{H}^{+}.$$ Acetaldehyde dehydrogenase is a(n) A. oxidoreductase. B. transferase. C. hydrolase. D. lyase. E. ligase.

A research technician who is working with organophosphate compounds is required to have a weekly blood test for acetylcholine esterase activity. Typically, esterase activity remains relatively constant for some time and then abruptly drops to zero. If this happens, the technician must immediately stop working with the organophosphate compounds. The organophosphate compounds form stable esters with a critical serine hydroxyl group in the esterase. Organophosphate compounds inactivate the esterase by A. competitive inhibition. B. uncompetitive inhibition. C. noncompetitive inhibition. D. suicide inhibition. E. irreversible inhibition.

When added to a reaction, a catalyst A. supplies the heats of formation. B. alters the equilibrium constant \(K_{\text {eq }}\) to favor the formation of products. C. increases the rate at which equilibrium is reached. D. changes the order of the reaction (e.g., first order to second order E. alters the \(\Delta G_{0}\) of the reaction.

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