(i) Given that the cell parameter for calcium oxide, which crystallizes with
the sodium chloride structure, is \(483 \mathrm{pm}\), calculate the lattice
energy for \(\mathrm{CaO}\).
(ii) Using the following data and the lattice energy calculated in part (i),
construct a thermochemical cycle for the formation of calcium oxide from its
elements and hence calculate the enthalpy of formation of
\(\mathrm{CaO}_{(\mathrm{s})}\) :
\(\Delta H_{\text {sub }}=+177 ;\) ionization potentials: first \(=+590 ;\) second
\(=\) \(+1100 ; \Delta H_{\text {diss }}=+498 ;\) first \(E_{\mathrm{a}}=142 ;\)
second \(E_{\mathrm{a}}=-844\left(\mathrm{~kJ} \mathrm{~mol}^{-1}\right)\)
(iii) Why might you expect the answer calculated in (ii) to have an error of
about \(5 \mathrm{~kJ} \mathrm{~mol}^{-1 ?}\)
(iv) Why is the second ionization potential for calcium much greater than the
first despite forming a stable closed-shell configuration?