Question

How many grams of perchloric acid, ${\mathbf{HCIO}}_{\mathbf{4}}$, are contained in $\mathbf{37}\mathbf{.}\mathbf{6}\mathbf{}\mathbf{g}$of $\mathbf{70}\mathbf{.}\mathbf{5}\mathbf{}\mathbf{wt}\mathbf{\%}$aqueous perchloric acid? How many grams of water are in the same solution?

Short answer

The quantity of ${\mathrm{HCIO}}_4$is $26.5\mathrm{g}$and the quantity of the water is $1.11\mathrm{g}$in an aqueous perchloric acid.

Step-by-step solution

The quantity of HCIO4 

The mass of a perchloric acid $\left({\mathrm{HCIO}}_4\right)$in $g$is as follows:

$$\begin{gathered} \mathrm{Mass}\mathrm{of}\mathrm{the}{\mathrm{HCIO}}_4=\frac{70.5}{100}\times 37.6 \\ =26.5\mathrm{g} \end{gathered}$$

The quantity of the water

The mass of the water in the same solution will be:

$$\begin{gathered} \mathrm{Mass}\mathrm{of}\mathrm{the}\mathrm{water}=37.6\mathrm{g}-26.5\mathrm{g} \\ =11.1\mathrm{g} \end{gathered}$$

Therefore, the quantity of the ${\mathrm{HCIO}}_4$is$26.5\mathrm{g}$ and the quantity of the water is $11.1\mathrm{g}$