Chapter 20: Q32P (page 527)
Explain how the difference voltage in Figure 20-37 reduces noise from source flicker.
Short Answer
The differential voltage minimises noise from source flicker.
Chapter 20: Q32P (page 527)
Explain how the difference voltage in Figure 20-37 reduces noise from source flicker.
The differential voltage minimises noise from source flicker.
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Get started for freeShow that a grating with 103 grooves/cm provides a dispersion of 5.88 per mm of wavelength if n 5 1 and f 5 108 in Equation 20-4.
Explain how an optical fibre works. Why does the fibre still work when it is bent?
Refer to the Fourier transform infrared spectrum in Figure 20-33.
(a) The interferogram was sampled at retardation intervals of. What is the theoretical wavenumber range (0 to ?) of the
spectrum?
(b) A total of 4 096 data points were collected from . Compute the value of, the maximum retardation.
(c) Calculate the approximate resolution of the spectrum.
(d) The interferometer mirror velocity is given in the figure caption. How many microseconds elapse between each datum?
(e) How many seconds were required to record each interfero gram once?
(f) What kind of beam splitter is typically used for the region 400 to 4 000? Why is the region below 400not observed?
The prism shown here is used to totally reflect light at aangle. No surface of this prism is silvered. Use Snell's law to explain why total reflection occurs. What is the minimum refractive index of the prism for total reflection?
The exitance (power per unit area per unit wavelength) from a blackbody (Box 20-1) is given by the Planck distribution: where is wavelength, Tis temperature K), his Planckโs constant, Cis the speed of light, and kis Boltzmannโs constant. The area under each curve between two wavelengths in the blackbody graph in Box 20-1is equal to the power per unit areaemitted between those two wavelengths. We find the area by integrating the Planck function between wavelengthsand
role="math" localid="1664862982839"
For a narrow wavelength range, the value of is nearly constant and the power emitted is simply the product .
(a) Evaluate and at
(b) Calculate the power emitted per square meter atin the intervalby evaluating the product
(c) Repeat part (b) for the interval
(d) The quantityis the relative exitance at the two wavelengths. Compare the relative exitance at these two wave-lengths atwith the relative exitance at 100K. What does your answer mean?
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