Question

What level of stray light gives an absorbance error of 0.01 at an absorbance of 2? That is, what value of Sgives an apparent absorbance of 1.99?

Short answer

The apparent transmittance equation is as follows:$S=2.428\times {10}^{-4}\%$

Step-by-step solution

Concept used

The remaining light can be tolerated if the calculated absorbance error is not exceeded.

The apparent transmittance equation is written: $\mathrm{S}=\frac{\mathrm{P}+\mathrm{S}}{{\mathrm{P}}_0+\mathrm{S}}$

The apparent absorbance can be computed using the following formula - logT

Step 2: Calculate the apparent transmittance

Given that,

The apparent transmittance is determined using the following formula:

True transmissibility is$={10}^{1.999}=0.010023$

$$\begin{gathered} S=\frac{P+S}{P_0+S}=\frac{0.010+S}{1+S} \\ =\frac{0.0366}{1.005} \\ =0.010023 \\ S=2.428\times {10}^{-4}\% \\ S=0.00024 \end{gathered}$$

Therefore, it is discovered that the apparent transmittance is_{$S=2.428\times {10}^{-4}\%$}