Question

Explain how to prepare a powder with an average particle diameter near \(100\mu m\) by using sieves from Table 28-2. How would such a particle mesh size be designated?

Short answer

The sample retained by\(170\) mesh sieve would have a size between\(0.090\;{\rm{mm}}\) and\(0.125\;{\rm{mm}}\), it would be called\(120/170\) mesh

Step-by-step solution

Definition of Standard deviation.

• The standard deviation is a measure of how far something deviates from the mean (for example, spread, dispersion, or spread). A "typical" variation from the mean is represented by the standard deviation.
• Because it returns to the data set's original units of measurement, it's a common measure of variability.
• The standard deviation, defined as the square root of the variance, is a statistic that represents the dispersion of a dataset relative to its mean.

Determine the particle mesh size be designated.

• In this task we will explain the preparation of a powder with an average particle diameter\(100\mu {\rm{m}}\)using the sieves from Table\(28 - 2\).

• First we will convert \(100\mu {\rm{m}}\) to\({\rm{mm}}\)in order to find the mesh:

\(100\mu {\rm{m}}= 0.1\;{\rm{mm}}\)

• Which would be between\(120 - 140 - 170\) sieve number (considering that values of screen opening from Table\(28 - 2\)are\(0.125 - 0.106 - 0.090\), which are all \(0.1\) mm)
• From Table \(28 - 2\) we can say that we would use a\(120\)mesh sieve, through which we would pass the powder and then proceed to the\(170\)mesh sieve

Therefore, the sample retained by\(170\)mesh sieve would have a size between\(0.090\;{\rm{mm}}\)and\(0.125\;{\rm{mm}}\), it would be called \(120/170\)mesh