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Barium titanate, a ceramic used in electronics, was analyzed by the following procedure: Into a Pt crucible was placed \(1.2\;{\rm{g}}\)of \({\rm{N}}{{\rm{a}}_2}{\rm{C}}{{\rm{O}}_3}\) and \(0.8\;{\rm{g}}\)of \({\rm{N}}{{\rm{a}}_2}\;{{\rm{B}}_4}{{\rm{O}}_7}\)plus \(0.3146\;{\rm{g}}\)of unknown. After fusion at \({1000^\circ }{\rm{C}}\)in a furnace for\(30\;{\rm{min}}\), the cooled solid was extracted with \(50\;{\rm{mL}}\)of\(6{\rm{MHCl}}\), transferred to a \(100 - {\rm{mL}}\) volumetric flask, and diluted to the mark. A \(25.00 - {\rm{mL}}\)aliquot was treated with \(5\;{\rm{mL}}\)of \(15\% \)tartaric acid (which complexes \({\rm{T}}{{\rm{i}}^{4 + }}\)and keeps it in aqueous solution) and \(25\;{\rm{mL}}\)of ammonia buffer,\({\rm{pH}}9.5\). The solution was treated with organic reagents that complex\({\rm{B}}{{\rm{a}}^{2 + }}\), and the \({\rm{Ba}}\)complex was extracted into \({\rm{CC}}{{\rm{l}}_4}.\)After acidification (to release the \({\rm{B}}{{\rm{a}}^{2 + }}\) from its organic complex), the \({\rm{B}}{{\rm{a}}^{2 + }}\)was backextracted into\(0.1{\rm{MHCl}}\). The final aqueous sample was treated with ammonia buffer and methylthymol blue (a metal ion indicator) and titrated with \(32.49\;{\rm{mL}}\) of \(0.01144{\rm{M}}\)EDTA. Find the weight per cent of Ba in the ceramic.

Short Answer

Expert verified

The weight percent of Ba in the ceramic is \(0.6049\)%.

Step by step solution

01

Defining the weight percent.

The Weight Percentage is simply the ratio of a solute's mass to the mass of a solution multiplied by 100. The Weight Percentage is also referred to as the Mass Percentage.

\(Percent by weight = \frac{{{\rm{ gram of solute }}}}{{100g{\rm{ of solution }}}}\)

02

Determining the moles of EDTA and \({\rm{B}}{{\rm{a}}^{2 + }}\).

Here \(1/4\)of the sample is required for EDTA titration so we will first calculate the moles of EDTA spent on titration:

\(n({\rm{EDTA}}) = c \times V\)

\(n({\rm{EDTA}}) = 0.01144{\rm{M}} \times (0.03249\;{\rm{L}})\)

\(n({\rm{EDTA}}) = 3.717 \times {10^{ - 4}}\;{\rm{mol}}\)

Next we will determine the moles of \({\rm{B}}{{\rm{a}}^{2 + }}\)and calculate its mass:

\(n\left( {{\rm{B}}{{\rm{a}}^{2 + }}} \right) = 4 \times n({\rm{ EDTA }})\)

\(n\left( {{\rm{B}}{{\rm{a}}^{2 + }}} \right) = 4 \times 3.717 \times {10^{ - 4}}\;{\rm{mol}} = 1.487 \times {10^{ - 3}}\;{\rm{mol}}\)

\( \to m\left( {{\rm{B}}{{\rm{a}}^{2 + }}} \right) = 0.2042\;{\rm{g}}\)

03

Determining the weight percent.

Now calculating the weight percent

\(wt\% = \frac{{m\left( {{\rm{B}}{{\rm{a}}^{2 + }}} \right)}}{{m({\rm{ unknown }})}}\)

\(wt\% = \frac{{0.2042\;{\rm{g}}}}{{0.3146\;{\rm{g}}}}\)

\(wt\% = 0.6049\)

Therefore the weight percent of Ba in the ceramic is \(0.6049\)%.

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Most popular questions from this chapter

What mass of sample in Figure 28-3 is expected to give a sampling standard deviation of \( \pm 6\% \)?

Referring to Table 28-7, explain how an anion-exchange resin can be used for absorption and analysis of \({\bf{S}}{{\bf{O}}_2}\)released by combustion.

In 2002, workers at the Swedish National Food Administration discovered that heated, carbohydrate-rich foods, such as french fries, potato chips, and bread, contain alarming levels \((0.1to4\mu {\rm{g}}/{\rm{g}})\) of acrylamide, a known carcinogen\(36\).

After the discovery, simplified methods were developed to measure ppm levels of acrylamide in food. In one procedure,\(10\;{\rm{g}}\) of pulverized, frozen french fries were mixed for \(20\;{\rm{min}}\)with\(50\;{\rm{mL}}\) of \({{\rm{H}}_2}{\rm{O}}\)to extract acrylamide, which is very soluble in water \((216\;{\rm{g}}/100\;{\rm{mL}}).\)The liquid was decanted and centrifuged to remove suspended matter. The internal standard \(^2{{\rm{H}}_3}\)-acrylamide was added to\(1\;{\rm{mL}}\) of extract. A solid-phase extraction column containing \(100{\rm{mg}}\)of cation-exchange polymer with protonated sulfonic acid groups\(\left( { - {\rm{S}}{{\rm{O}}_3}{\rm{H}}} \right.)\) was washed twice with 1 -mL portions of methanol and twice with \(1 - {\rm{mL}}\)portions of water. The aqueous food extract \((1{\rm{mL}})\)was then passed through the column to bind protonated acrylamide \(\left( { - {\rm{NH}}_3^ + } \right)\)to sulfonate \(\left( { - {\rm{SO}}_3^ - } \right)on\)the column. The column was dried for\(30\;{\rm{s }}at\)\(0.3\)bar and then acrylamide was eluted with\(1\;{\rm{mL}}\) of \({{\rm{H}}_2}{\rm{O}}.\)Eluate was analyzed by liquid chromatography with a polar bonded phase. The chromatograms show the results moni- tored by ultraviolet absorbance or by mass spectrometry. The retention time of acrylamide is different on the two columns because they have different dimensions and different flow rates.

(a) What is the purpose of solid-phase extraction prior to chromatography? How does the ion-exchange sorbent retain acrylamide?

(b) Why are there many peaks when chromatography is monitored by ultraviolet absorbance?

(c) Mass spectral detection used selected reaction monitoring (Figure 22-33) with the \(m/z72 \to 55\)transition for acrylamide and \(75 \to 58fo{r^2}{{\rm{H}}_3}\)-acrylamide. Explain how this detection method works and suggest structures for the ions with \({\rm{m}}/{\rm{z}}72\)and 55 from acrylamide.

(d) Why does mass spectral detection give just one major peak?

(e) How is the internal standard used for quantitation with mass spectral detection?

(f) Where does \(^2{{\rm{H}}_3}\)-acrylamide appear with ultraviolet absorbance? With mass spectral selected reaction monitoring?

(g) Why does the mass spectral method give quantitative results even though retention of acrylamide by the ion-exchange sorbent is not quantitative and elution of acrylamide from the sorbent by \(1\;{\rm{mL}}\) of water might not be quantitative?

Chromatograms of acrylamide extract after passage through solid-phase extraction column. Left: Phenomenex Synergi Polar-RP 4- \(\mu {\rm{m}}\)column eluted with 96:4 \((vol/vol){{\rm{H}}_2}{\rm{O}}:{\rm{C}}{{\rm{H}}_3}{\rm{CN}}.\)Right: Phenomenex Synergi Hydro-RP 4- \(\mu {\rm{m}}\)column eluted with \(96:4:0.1(vol/vol/vol){{\rm{H}}_2}{\rm{O}}:{\rm{C}}{{\rm{H}}_3}{\rm{OH}}:{\rm{HC}}{{\rm{O}}_2}{\rm{H}}.\) (Data from L. Peng. T. Farkas, L. Loo, \({\rm{J}}.\)Teuscher, and \({\rm{K}}.\)Kallury, "Rapid and Reproducible Extraction of Acrylamide in French Fries Using a Single Solid-Phase Sorbent," Am. Lab. News Ed, October 2003, p. 10.)

How does solid-supported liquid-liquid extraction differ from solid-phase extraction?

EXAMPLE- Particles designated \(50/00\)mesh pass through a 50 mesh sieve bou are retained by a lo0 mesh sieve. Their size is in the range 0.150-0.300 mm.

does not pass is retained for your sample. This procedure gives particles whose diameters are in the range \(0.85 - 1.18\;{\rm{mm}}.\) We refer to the size range as \(16/20{\rm{mesh}}.\)

Suppose that much finer particles of \(80/120\)mesh size (average diameter \( = 152\mu {\rm{m}},\) average volume\( = 1.84\;{\rm{nL}}\)) were used instead. Now the mass containing \({10^4}\) particles is reduced from \(11.0to0.0388\;{\rm{g}}.\) We could analyze a larger sample to reduce the sampling uncertainty for chloride.

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