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What is the difference between a false positive and a false negative?

Short Answer

Expert verified

A false positive is an error that shows up when results are interpreted as positive (e.g. something is present when it's actually not, something is detected as above the limit when it's actually below the limit), while a false negative says the other way around (e.g. Something is identified as being below the limit when it is actually above the limit, and something is recognised as being absent when it is truly present).

Step by step solution

01

Definition of false positive and false negative.

False positive:

In analytical Chemistry, False positive is an assumption that the concentration of analyte goes above a certain limit, in fact the concentration is below the limit.

False negative:

In analytical Chemistry, False negative is an assumption that the concentration of analyte is lower than a certain limit. In fact, the concentration is above the limit.

02

Difference between false positive and false negative

When you get a positive test result when you should have gotten a negative result, it's known as a false positive. It's also known as a "false positive error" or "false alarm." It's most commonly employed in the medical area, but it can be applied to other fields as well (like software testing).

Examples:

  • A pregnancy test indicates that you are pregnant when you are not.
  • You have a positive cancer screening test, but you don't have the disease.
  • A prenatal test for Down's Syndrome comes up positive even though your foetus does not have the disorder.
  • Your computer's virus software wrongly classifies a safe programme as harmful.

When a negative test result is incorrect, it is referred to as a false negative.To put it another way, you get a negative test result when you should have had a positive one. For instance, suppose you take a pregnancy test and it comes back negative (not pregnant). You are, however, expecting a child. It's possible that you got a false negative on a pregnancy test because you took it too soon, used diluted urine, or checked the findings too quickly. A false negative is a possibility with almost every diagnostic test. A cancer test, for example, could come back negative when you truly have the condition.

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Most popular questions from this chapter

A solution containing3.47mMX(analyte) and1.72mMS(standard) gave peak areas of3473and 10222,respectively, in a chromatographic analysis. Then1.00mLof 8.47mMSwas added to5.00mLof unknownX,and the mixture was diluted to10.00mL. This solution gave peak areas of5428and4431forXandS, respectively.

(a) Calculate the response factor for the analyte.

(b) Find the concentration of S(mM)inthe10.0-mLmixture.

(c) Find the concentration of X(mM)inthe10.0-mLmixture.

(d) Find the concentration ofXintheorignalunknown.

Chloroform is an internal standard in the determination of the pesticide DDT in a polarographic analysis in which each compound is reduced at an electrode surface. A mixture containing 0.500mMchloroform and0.800mMDDT gave signals of15.3ฮผAfor chloroform and10.1ฮผAfor DDT. An unknown solution(10.0mL)containing DDT was placed in a100-mLvolumetric flask and10.2ฮผLof chloroform (FM 119.39, density=1.484g/mL)were added. After dilution to the mark with solvent, polarographic signals of and8.7ฮผAwere observed for the chloroform and DDT, respectively. Find the concentration of DDT in the unknown.

In Figure 5-6, the x-intercept is -2.89mMand its standard uncertainty is0.098mM. Find the90%and99%confidence intervals for the intercept.

1.00 mL of blood serum was diluted to 25.00 mL in each flask of a standard addition experiment like Figure 5-7 to measure a hormone with a molecular mass of 373 g/mol. The x-intercept of the graph was 4.2 ppb (parts per billion). Find the concentration of hormone in the serum and express your answer in ppb and molarity. Assume that the density of serum and all solutions is close to 1.00 g/mL

Detection limit. In spectrophotometry, we measure the concentration of an analyte by its absorbance of light. A low-concentration sample was prepared and nine replicate measurements gave absorbances of 0.0047,0.0054,0.0062,0.0060,0.0046,0.0056,0.0052,0.0044, and 0.0058. Nine reagent blanks gave values of 0.0006,0.0012, 0.0022,0.0005,0.0016,0.0008,0.0017,0.0010, and 0.0011.

a) Find the absorbance detection limit with equation 5-3.

b) The calibration curve is a graph of absorbance versus concentration. Absorbance is a dimensionless quantity. The slope of the calibration curve is m=2.24x104M-1Find the concentration detection limit with Equation 5-5.

(c) Find the lower limit of quantitation with Equation 5-6.

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