Question

Compute the pH of ${}^{\mathbf{0}\mathbf{.}\mathbf{010}\mathbf{M}}$HHis.

Short answer

The pH of ${}^{\mathbf{0}\mathbf{.}\mathbf{010}\mathbf{M}\mathbf{}\mathbf{His}}$ is discovered to be${}^{\mathbf{pH}\mathbf{}\mathbf{=}\mathbf{7}\mathbf{.}\mathbf{62}}$.

Step-by-step solution

Definition of Metallic elements and non metallic elements

• The pH scale is a measurement of how acidic or al.
• The pH scale was created to quantify the concentration of hydrogen ions in a solution, and the p in pH stands for 'potenz' in German.

Determine the pH of  HHis.

The pH of ${}^{\mathbf{0}\mathbf{.}\mathbf{010}\mathbf{MH}}$His must be calculated.

The diprotic form's intermediate form

$\mathbf{\left[}{\mathbf{H}}^{\mathbf{+}}\mathbf{\right]}\mathbf{}\mathbf{=}\sqrt{\frac{{\mathbf{K}}_{\mathbf{2}}\mathbf{+}{\mathbf{K}}_{\mathbf{3}}\mathbf{}\mathbf{F}\mathbf{+}{\mathbf{K}}_{\mathbf{2}}\mathbf{}{\mathbf{K}}_{\mathbf{w}}}{{\mathbf{K}}_{\mathbf{2}}\mathbf{}\mathbf{+}\mathbf{}\mathbf{F}}}$

The equilibrium constants that should be used are as follows ${}^{{\mathbf{K}}_{\mathbf{2}}}$and ${}^{{\mathbf{K}}_{\mathbf{3}}}$in place of and ${}^{{\mathbf{K}}_{\mathbf{2}}}$

0.10MHHis: it get 10-14 it follow the equation.

$$\begin{gathered} \left[H^{+}\right]\mathbf{=}\sqrt{\frac{\left({10}^{5.97}\right)\left({10}^{.928}\right)\left(0.10\right)\left({10}^{5.97}\right)\left(1.0\times {10}^{-14}\right)}{{\mathbf{10}}^{\mathbf{5}\mathbf{.}\mathbf{97}}\mathbf{+}\mathbf{0}\mathbf{.}\mathbf{10}}} \\ \mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{=}\mathbf{2}\mathbf{.}\mathbf{37}\mathbf{\times }{\mathbf{10}}^{\mathbf{-}\mathbf{8}}\mathbf{}\mathbf{M} \\ \mathbf{pH}\mathbf{=}\mathbf{7}\mathbf{.}\mathbf{62} \end{gathered}$$

This is similar to${}^{\frac{\mathbf{1}}{\mathbf{2}}\left({\mathrm{pK}}_2+{\mathrm{pK}}_3\right)\mathbf{}\mathbf{=}\mathbf{7}\mathbf{.}\mathbf{62}}$

The pH ofis discovered to be ${}^{\mathbf{pH}\mathbf{=}\mathbf{7}\mathbf{.}\mathbf{62}}$