Question

The retention volume of a solute is 76.2mL for a column with${\mathbf{V}}_{\mathbf{m}}\mathbf{=}\mathbf{16}\mathbf{.}\mathbf{6}\mathbf{mL}$ and${\mathbf{V}}_{\mathbf{s}}\mathbf{=}\mathbf{12}\mathbf{.}\mathbf{7}\mathbf{mL}$ . Calculate the retention factor and the partition coefficient for this solute.

Short answer

1. Retention factor = k = 3.59
2. Partition coefficient= K = 4.69

Step-by-step solution

Given Information:

${\mathrm{V}}_{\mathrm{r}}=76.2\mathrm{mL},{\mathrm{V}}_{\mathrm{m}}=16.6\mathrm{mL},{\mathrm{V}}_{\mathrm{s}}=12.7\mathrm{mL}$

To find the Retention factor:

Retention factor as

$\mathrm{k}=\frac{{\mathrm{V}}_{\mathrm{r}}-{\mathrm{V}}_{\mathrm{m}}}{{\mathrm{V}}_{\mathrm{m}}}$

Substitute the given data values are

$$\begin{gathered} \mathrm{k}=\frac{76.2\mathrm{mL}-16.6\mathrm{mL}}{{\mathrm{V}}_{\mathrm{m}}} \\ \mathrm{k}=3.59 \end{gathered}$$

To find the Partition coefficient;

$\mathrm{K}=\mathrm{k}\times \frac{{\mathrm{V}}_{\mathrm{m}}}{{\mathrm{V}}_{\mathrm{s}}}$

Substitute the given data values are

$$\begin{gathered} \mathrm{k}=3.59\times 16.6\mathrm{mL} \\ \mathrm{K}=4.69 \end{gathered}$$