Question

The retention volume of a solute is 76.1mL for a column with${\mathit{V}}_{\mathbf{m}}\mathbf{=}\mathbf{16}\mathbf{.}\mathbf{6}\mathit{m}\mathit{L}$ and${\mathit{V}}_{\mathbf{s}}\mathbf{=}\mathbf{12}\mathbf{.}\mathbf{7}\mathit{m}\mathit{L}$ . Calculate the retention factor and the partition coefficient for this solute.

Short answer

a) Retention factor =k =3.59

b) Partition coefficient=k = 4.69

Step-by-step solution

Given Information:

$V_r=76.2mL,V_m=16.6mL,V_s=12.7mL$

To find the Retention factor:

Retention factor as

$k=\frac{V_r-V_m}{V_m}$

Substitute the given data values are

$$\begin{gathered} k=\frac{76.2mL-16.6mL}{16.6mL} \\ k=3.59 \end{gathered}$$

To find the Partition coefficient;

$K=k\times \frac{V_m}{V_s}$

Substitute the given data values are

$$\begin{gathered} K=3.59\times \frac{16.6mL}{12.7mL} \\ K=4.69 \end{gathered}$$