Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

23-1.If you are extracting a substance from water into ether, is it more effective to do one extraction with of ether or three extractions with ?

Short Answer

Expert verified

When a substance gets extracted from water into ether, we could determine whether it is more effective to do one extraction with 300mL of ether or three extractions with 100mL of ether.

Step by step solution

01

of 4

  • Here, let us extract the substance from water by using either as a solvent.
  • This process is done while using either as a solvent as that substance is considered to be more soluble in organic solvent.
02

of 4

  • If we have ever done with such kind of extraction before, we would have known that with first extraction and even with the second one, there is still some substance left in the solvent which we leave in the separatory funnel.
  • It is to be noted that we leave it intentionally because we don’t want the water (contains impurities + substance) to drop in our beaker with pure solvent + substance.
03

of 4

  • Let us imagine that with first extraction we extracted 95% of our substance from water and there is still 5% of it left in the water.
  • When the process gets repeated once again, we would extract 95% from those 5% left in the water so we would get a total of 0.95×5%=4.75% (now there is a 0.25 % of the substance left in the water).
  • When the process gets repeated again, we would get 0.95×0.25%=0.2375% .
  • Finally, we would have a total of (95 + 4.75 + 0.2375)%R=99.99% extracted substance.
04

0f 4

  • Hence, it would be better to do three extractions with 100mLthan one with 300mL.
  • It is to be noted that the volume is almost irrelevant when doing extractions.

Result:

Thus, it would be better to do three extractions with 100mL than one with 300mL.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Match statements 1–5 with the band broadening terms in the second list.

1. Depends on radius of open tubular column.

2. Not present in an open tubular column.

3. Depends on length and radius of connecting tubing.

4. Increases with diffusion coefficient of solute.

5. Increases with thickness of stationary phase film.

A Multiple paths

B Longitudinal diffusion

Cm Equilibration time in mobile phase

Cs Equilibration time in stationary phase

EC Extra column band broadening

A chromatographic procedure separatesof unknown mixture on a column with a length of 40cmand a diameter of 0.85cm . (a) What size column would you use to separate 100mgof the same mixture? (b) If the flow is 0.22mL/minon the small column, what volume flow rate should be used on the large column? (c) The mobile phase occupies 35%of the column volume. Calculate the linear velocity for the small column and the large column.

The weak base B(Kb=1.0×10-5)equilibrates between water (phase 1) and benzene (phase 2)

(a) Define the distribution coefficient, D for this system.

(b) Explain the difference between D and K the partition coefficient.

(c) Calculate D at pH8.00ifk=50.0

(d) Will D be greater or less at pH10thanatpH8? Explain why.

The solute in Problem 23 - 8 is initially dissolved in 80.0 mL of water. It is then extracted six times with 10.0mL portions of chloroform. Find the fraction of solute remaining in the aqueous phase.

(a) Explain why the diffusion coefficient of CH3OHis greater than that of

sucrose in Table 23-1.

(b) Make an order-of-magnitude estimate of the diffusion coefficient of water

vapor in air at 298K.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free