Chapter 27: Q30P (page 769)
Why is tin used to encapsulate a sample for combustion analysis?
Short Answer
To explain the reason why tin is used to encapsulate a sample for combustion analysis.
Chapter 27: Q30P (page 769)
Why is tin used to encapsulate a sample for combustion analysis?
To explain the reason why tin is used to encapsulate a sample for combustion analysis.
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Get started for freeA method to measure soluble organic carbon in seawater includes oxidation of the organic materials to CO2 with K2S2O8, followed by gravimetric determination of the CO2 trapped by a column 0f Ascarite. A water sample weighing 6.234 g produced 2.378 mg of CO2(FM 44.009). Calculate the ppm carbon in the seawater.
An organic compound with a formula mass of 417g/molwas analyzed for ethoxyl groups by the reactions
A 25.42-mg sample of compound produced How many ethoxyl groups are there in each molecule?
A 50.00-mL solution containingwas treated with excess AgNo3 to precipitate 0.2146 g of AgBr (FM 187.772). What was the molarity of NaBr in the solution?
Man in the vat problem.15 Long ago, a workman at a dye factory fell into a vat containing hot, concentrated sulfuric and nitric acids. He dissolved completely! Because nobody witnessed the accident, it was necessary to prove that he fell in so that the manโs wife could collect his insurance money. The man weighed 70 kg, and a human body contains |6.3 parts per thousand (mg/g) phosphorus. The acid in the vat was analyzed for phosphorus to see whether it contained a dissolved human.
(a) The vat containedof liquid, and a 100.0-mL sample was analyzed. If the man did fall into the vat, what is the expected quantity of phosphorus in 100.0 mL?
(b) The 100.0-mL sample was treated with a molybdate reagent that precipitated ammonium phosphomolybdate,This substance was dried atto remove waters of hydration and heated tountil it reached the constant composition, which weighed 0.371 8 g. When a fresh mixture of the same acids (not from the vat) was treated in the same manner, 0.033 1 g ofwas produced. This blank determination gives the amount of phosphorus in the starting reagents. Thethat could have come from the dissolved man is therefore.How much phosphorus was present in the 100.0-mL sample? Is this quantity consistent with a dissolved man?
Marie Curie dissolved 0.091 92 g of RaCl2 and treated it with excess AgNO3to precipitate 0.088 90 g of AgCl. In her time (1900), the atomic mass of Ag was known to be 107.8 and that of Cl
was 35.4. From these values, find the atomic mass of Ra that Marie Curie would have calculated.
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