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Use Table 24-2 to predict the elution order of the following compounds from columns containing (a) poly (dimethyl siloxane), (b) (diphenyl)0.35(dimethyl)0.65polysiloxane, and (c) poly (ethylene glycol): hexane, heptane, octane, benzene, butanol, 2-pentanone.

Short Answer

Expert verified

a)hexane, benzene=butanol, 2-pentanone, heptane, octane

b)hexane, heptane, butanol =2-pentanone, benzene, octane

c) hexane, heptane, octane, benzene, 2-pentanone, butanol

Step by step solution

01

 a) poly (dimethyl siloxane)

Retention indexes for straight chain alkanes are fixed and do not depend on the stationary phase. From Table 24-2, the values of the retention index of the given compounds are:

- hexane =600

- heptane =700

- octane =800

The retention index determines the elution order of the compounds; the order is identified based from the lowest to highest value.

Determine the retention indexes of the other given compounds for this stationary phase.

- benzene =651

- butanol = 651

- 2-pentanone =667

Thus, the elution order is:

hexane, benzene=butanol, 2-pentanone, heptane, octane

02

Step 2:b) ( diphenyl)0.35(dimethyl)0.65 polysiloxane

Determine the retention indexes of the other given compounds for this stationary phase.

- benzene =746

- butanol =733

- 2-pentanone =733

Thus, the elution order is:

hexane, heptane, butanol =2-pentanone, benzene, octane

03

  Step 3: c) poly (ethylene glycol)

Determine the retention indexes of the other given compounds for this stationary phase.

- benzene =963

- butanol = 1158

- 2 -pentanone =998

Thus, the elution order is:

hexane, heptane, octane, benzene, 2-pentanone, butanol

04

final answer

a)hexane, benzene=butanol, 2-pentanone, heptane, octane

b)hexane, heptane, butanol =2-pentanone, benzene, octane

c) hexane, heptane, octane, benzene, 2-pentanone, butanol

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Most popular questions from this chapter

Heptane, decane, and an unknown had adjusted retention times of 12.6min(heptane),22.9min(decane), and20.0min(unknown). The retention indexes for heptane and decane are 700 and 1000 , respectively. Find the retention index for the unknown.

This problem reviews concepts from Chapter 23 using

Figure 24-7.

(a) Calculate the number of theoretical plates (N in Equation 23-30)

and the plate height (H) for CO.

(b) Find the resolution (Equation 23-23) between argon and oxygen.

This problem reviews concepts from Chapter 23. An unretained solute passes through a chromatography column in 3.7 min and analyte requires 8.4 min.

(a) Find the adjusted retention time and retention factor for the analyte.

(b) Find the phase ratio b for a 0.32-mm-diameter column with a 1.0-mm-thick film of stationary phase.

(c) Find the partition coefficient for the analyte.

(d) Determine the retention time on a similar length of 0.32-mm diameter column with a 0.5-mm-thick film of the same stationary phase at the same temperature.

(a) If retention times are 1.0 min for CH4, 12.0 min for octane, 13.0 min for unknown, and 15.0 min for nonane, find the Kovats retention index for the unknown. (b) What would be the Kovats index for the unknown if the phase ratio of the column were doubled? (c) What would be the Kovats index for the unknown if the length of the column were halved

(a) Why is it illogical to use a thin stationary phase (0.2 ยตm) in a wide-bore (0.53-mm) open tubular column?

(b) Consider a narrow-bore (0.25 mm diameter), thin-film (0.10 ยตm) column with 5 000 plates per meter. Consider also a wide-bore (0.53 mm diameter), thick-film (5.0 ยตm) column with 1500 plates per meter. The density of stationary phase is approximately 1.0 g/mL. What mass of stationary phase is in each column in a length equivalent to one theoretical plate? How many nanograms of analyte can be injected into each column if the mass of analyte is not to exceed 1.0% of the mass of stationary phase in one theoretical plate?

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