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Express the molecular mass ±uncertaintyof C9H9O6N3 with the correct number of significant figures.

Short Answer

Expert verified

The molecular mass ±uncertaintyof C9H9O6N3 with the correct number of significant figures = 255.18402±0.0002g/mol

Step by step solution

01

To find

The molecular mass ±uncertainty ofC9H9O6N3 with the correct number of significant figures.

02

Atomic masses of atoms in the given compound

The atomic mass of a given compound C9H9O6N3is written below:

C=12.0106±0.0002/3g/molH=1.00798±0.00002/3g/molO=15.9994±0.0002/3g/molN=14.0068±0.0002/3g/mol

03

Calculate molecular mass of the compound

The standard uncertainty in atomic mass equals to the uncertainty listed in the PSE divided by 3.

The molecular mass is calculated by the following:

M=9C+9H+60+3N=255.18402g/mol

04

Calculate the standard uncertainty

e=0.00022/3+0.000022/3+0.00022/3+0.00022/3=0.0002

This is the molar mass with uncertainty of:

255.18402±0.0002g/mol

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Most popular questions from this chapter

Find the absolute and percent relative uncertainty and express each answer with a reasonable number of significant figures.

a)9.23±0.03+4.21±0.02-3.26±0.06=?b)91.3±1.0×40.3±0.02/21.1±0.02=?c)4.97±0.05-1.86±0.01/21.1±0.02=?d)2.0164±0.0008+1.233±0.002+4.61±0.01=?e)2.0164±0.0008×103+1.233±0.002×102+4.61±0.01×101=?f)3.14±0.051/3=?g)log3.14±0.051/3=?

Write each answer with the correct number of significant figures.

(a)1.0+2.1+3.4+5.8=12.3000

(b) 106.9 - 31.4 = 75.5000

(c)107.868(2.113×102)+(5.623×103)=5519.568

(d)(26.14/37.62)×4.38=3.043413

(e(26.14/37.62×108)×(4.38×10-2)=3.043413×10-10

(f)(26.14/3.38)+4.2=4.5999

(g)log(3.98×104)=4.5999

(h)10-6.31=4.89779×10-7

Suppose that you used smaller volumetric apparatus to prepare 0.250MNH3solution by diluting role="math" localid="1663558223400" 84.6±0.8μL of 28.0±0.5 wt\% NH3 up to 5.00±0.02mL. Find the uncertainty in0.250M.(Answer: 0.250±0.005M.The uncertainty in density of concentratedNH3overwhelms all other smaller uncertainties in this procedure.)

We can measure the concentration of HCI solution by reaction with pure sodium carbonate: 2H++Na2CO32Na++H20+105.9884±0.0007required 27.35±0.04mLof HCI .

(a) Find the formula mass (and its uncertainty) for Na2CO3.

(b) Find the molarity of the HCI and its absolute uncertainty.

(c) The purity of primary standard Na2CO3is stated to be 99.95 to 100.5wt % , which means that it can react with (100.00±0.05)%of the theoretical amount of H+. Recalculate your answer to (b) with this additional uncertainty.

If uncertainty in pHis doubledto±0.06, what is the relative uncertainty in[H+]?

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