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Round each number as indicated:

  1. 1.236 7 to 4 significant figures
  2. 1.238 4 to 4 significant figures
  3. 0.315 2 to 3 significant figures
  4. 2.051 to 2 significant figures
  5. 2.005to 3 significant figures

Short Answer

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Step by step solution

01

The rules of rounding

Rounding rules:

1. If the digit immediately adjacent to the final digit to be retained is less than 5, the last digit is retained and all other digits are deleted.

2. If the digit is more than 5, the final digit to be kept is increased by one, and all other digits to its right are removed.

3. If the digit is 5, the last significant figure is left intact if the number is even and increased by one if the number is odd.

02

The four significant digits of 1.236 7

(a)

Round the 1.236 7 value to 4 significant figures as follows:

There are five important figures in the amount 1.236 7.

Drop the last digit 7 to round 1.236 7 to four significant figures.

Add 1 to 6 (the fourth digit of 1.236 7 ) since the digit 7 is more than halfway (more than ).

As a result, we receive 1.237 after rounding to four significant figures.

03

The four significant digits of 1.238 4

(b) Round the 1.238 4 figure to four significant figures as follows:

There are five significant figures in the number 1.238 4.

Drop the last digit 4 to round 1.238 4 to four significant digits.

The fourth digit 8 is treated the same as the fourth digit because it is less than halfway (less than 5 ). As a result, we receive 1.238 after rounding to four significant figures.

04

The four significant digits of 0.135 2

(c)

Round the number 0.135 2 to the nearest three significant figures:

There are four major figures in the amount 0.135 2.

Drop the last digit 2 to round 0.135 2 to three significant digits.

The third digit 5 is assumed to be the same as the digit 2 because it is less than halfway (less than 5 ). As a result, 0.135 we get after rounding to three significant figures.

05

The four significant digits of 2.051

(d)

Round the number 2.051 to the nearest two significant figures:

There are four major figures in the number 2.051.

Drop the last digits 51 to round 2.051 to two meaningful digits.

Because 51 is greater than halfway, add 1 to 0 (the second digit of 2.051) to get 2.1 after rounding to two significant digits.

06

The four significant digits of 2.005 0

(e)

Round the 2.005 0 value to three significant figures as follows:

There are five important figures in the number 2.005 0.

Drop the last numbers 50 to round 2.005 0 to three meaningful digits.

Because 50 is exactly halfway between two numbers, round the third digit of 2.005 0 to the nearest even number.

As a result, we receive 2.00 after rounding to three significant figures.

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Most popular questions from this chapter

Write the formula mass of (a) BaF2and (b)C6H4O4with a reasonable number of digits. Use the periodic table inside the cover of this book to find atomic masses.

Write each answer with a reasonable number of figures. Find the absolute and percent relative uncertainty for each answer.

(a)[12.41(ยฑ0.09)รท4.16(ยฑ0.01)]ร—7.0682(ยฑ0.0004)=?

(b)[3.26(ยฑ0.10)ร—8.47(ยฑ0.05)]-0.18(ยฑ0.06)=?(c)6.843(ยฑ0.008)ร—104รท[2.09(ยฑ0.04)-1.63(ยฑ0.01)]=?(d)3.24ยฑ0.08=?(e)(3.24ยฑ0.08)4=?(f)log(3.24ยฑ0.08)=?(g)103.24ยฑ0.08=?

Rewrite the number 3.123 56 (ยฑ0.167 89%) in the forms (a) number (ยฑ absolute uncertainty) and (b) number (ยฑ percent relative uncertainty) with an appropriate number of digits.

Suppose that you used smaller volumetric apparatus to prepare 0.250MNH3solution by diluting role="math" localid="1663558223400" 84.6ยฑ0.8ฮผL of 28.0ยฑ0.5 wt\% NH3 up to 5.00ยฑ0.02mL. Find the uncertainty in0.250M.(Answer: 0.250ยฑ0.005M.The uncertainty in density of concentratedNH3overwhelms all other smaller uncertainties in this procedure.)

You have a stock solution certified by a manufacturer to contain 150.0ยฑ0.3ฮผgSO42-/mL. You would like to dilute it by a factor of 100 to obtain 1.500ฮผg/mL. Two possible methods of dilution are stated below. For each method, calculate the resulting uncertainty in concentration. Use manufacturer's tolerances in Tables 2-3 and 2-4 for uncertainties. Explain why one method is more precise than the other.

(a) Dilute 10.00mL up to 100mL with a transfer pipet and volumetric flask. Then take 10.00mL of the dilute solution and dilute it again to 100mL.

(b) Dilute 1.000mL up to 100mL with a transfer pipet and volumetric flask.

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