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Cathodic stripping of CIO4-in Figure 17-26does not involve oxidation or reduction ofCIO4-. Explain how this measurement works.

Short Answer

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The measurement of cathodic stripping of perchlorate has been explained.

Step by step solution

01

Define cyclic voltammogram

Cathodic stripping voltammetry (CSV) is the quantification of metals species from their reduction current. The stripping bit means that there is a preconcentration step that usually consists of the adsorption of a complex with a selective ligand (usually an organic ligand) on the electrode. The metal in the complex is reduced. The sensitivity is very good because the adsorption forms a single molecular layer that is reduced in its entirety. There is no diffusion during the scan so a high scan rate can be used which gives a high sensitivity. The sensitivity of CSV is sufficient to detect about 20 elements in seawater.

In the electrochemical reactions, the relation between current and voltage is noted and this technique is called voltammetry. A graph that represents current Vs voltage is called a voltammogram.

02

Determine the measurement of cathodic stripping of perchlorate.

poly(3-octylthiophene) is coated on a gold electrode and on oxidizing, the polymer can conduct electrons. It is over-coated with poly(vinyl chloride) (PVC)and dipped in the sample of drinking water that contains lithium sulfate and spinning at four rpm liquid transport to electrode.CIO4-ion is soluble in the membrane. In the oxidation step,CIO4-transferred into the membrane to equal the charge of oxidized poly(3-octylthiophene). The electrode potential is changed from 0.83 to 0.3 V at 0.1V / s to lessen poly(3-octylthiophene) to its normal form and eject CIO4-from PVC membrane. During stripping, the peak current is measured-CIO4- concentration in drinking water.

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Most popular questions from this chapter

A dilute Na2SO4solution is to be electrolyzed with a pair of smooth Pt electrodes at a current density of 100A/m2and a current of 0.100A. The products areH2(g)andO2(g)at1.00barandatbar. Calculate the required voltage if the cell resistance is2.00Ωand there is no concentration polarization. What voltage would be required if the Pt electrodes were replaced by Au electrodes?

What is the purpose of the Nafion the membrane in Figure 17-33

cd2+was used as an internal standard in the analysis of Pb2+by square wave polarography. Cd2+gives a reduction wave at -0.60 V and Pb2+gives a reduction wave at –0.40 V. It was first verified that the ratio of peak heights is proportional to the ratio of concentrations over the whole range employed in the experiment. Here are results for known and unknown mixtures:

The unknown mixture was prepared by mixing 25.00(±0.05)mLof unknown (containing only Pb2+) plus 10.00(±0.05)mLof 3.23(±0.01)×10-4MCd2+and diluting to 50.00(±0.05)mL.

(a) Disregarding uncertainties, find [Pb2+]in the undiluted unknown.

(b) Find the absolute uncertainty for the answer to part (a).

Calculate the cathode potential (versus S.C.F.) needed to reduce cobalt(II) to 1.0μMin each of the following solutions. In each case, Co(s) is the product of the reaction. (Disregard any overpotential.)

(a) 0.10MHClO4

(b)0.10MC2O42-(Find the potential at which)[Co(C2O4)22-]=1.0μM

role="math" localid="1668354628300" Co(C2O4)22-+2c-Co(s)+2C2O42-E°=-0.474V

(c)0.10MFIJTA at pH 7.00(Find the potential at whichCo(HI)TA)2-=1.0μM.)

For a rotating disk electrode operating at sufficiently great potential, the redox reaction rate is governed by the rate at which analyte diffuses through the diffusion layer to the electrode (Figure 17-15b). The thickness of the diffusion layer is

δ=1.61D1/3V1/6ω-1/2

whereis the diffusion coefficient of reactant (m2/s),vis the kinematic viscosity of the liquid

(=viscosity/debsity=(m2/s),v and ωis the rotation rate (radians/s) of the electrode. There are 2π radians in a circle. The current densityis localid="1655441451764" (A/m2)is

localid="1655441445229" Currentdebsity=0.62nFD2/3v-1/6ω1/2C0

where nis the number of electrons in the half-reaction, Fis the Faraday constant, and localid="1655441459070" C0is the concentration of the electroactive species in bulk solution localid="1655441466748" (mol/m3,notmol/L) Consider the oxidation oflocalid="1655441474339" Fe(CN)64-in a solution of localid="1655441479067" 10.0mMK3Fe(CN)6+50.0mMK4Fe(CN)6at +0.90V(versus S.C.E.) at a rotation speed oflocalid="1655441490849" role="math" 2.00×103revolutions per minute. 27The diffusion coefficient oflocalid="1655441497131" Fe(CN)64-is2.5×10-9m2/sand the kinematic viscosity islocalid="1655441503345" 1.1×10-5m2/sCalculate the thickness of the diffusion layer and the current density. If you are careful, the current density should look like the value in Figure 17-16b.

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