Question

How many hours are required for 0.100 mol of electrons to flow through a circuit if the current is 1.00 A?

Short answer

Total hours requires for electrons to flow through a circuit is t = 2.68h

Step-by-step solution

Step1: Determination of electrons:

• Electrons move through a wire from the negative end to the positive end.
• The resistor uses the energy of the electrons around the wire and slows down the flow of electrons.

 Calculation of electrons:

Given data,

$\mathrm{n}\left({\mathrm{e}}^{-}\right)=0.1\mathrm{moll}=1\mathrm{At}=?$

The charge of electrons is calculated

$\mathrm{n}\left({\mathrm{e}}^{-}\right)=\frac{\mathrm{q}}{\mathrm{n}.\mathrm{F}}$

The is 1, so the q is,

$$\begin{gathered} \mathrm{q}=\mathrm{n}\left({\mathrm{e}}^{-}\right).\mathrm{F} \\ \mathrm{q}=0.1\mathbf{mol}.96485\mathbf{}\mathbf{C}\mathbf{/}\mathbf{mol} \\ \mathrm{q}=9648.5\mathbf{C} \end{gathered}$$

Step 3: Ascertaining the flow of current in hours:

Now we can calculate using the formula,

$\mathrm{q}=\mathrm{l}.\mathrm{t}$

Where is,

$$\begin{gathered} \mathrm{t}=\frac{\mathrm{q}}{\mathrm{l}}=\frac{9648.5\mathbf{C}}{1\mathbf{A}} \\ \mathrm{t}=9648.5\mathbf{s}=2.68\mathbf{h} \end{gathered}$$