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Calcium ion was titrated with EDTA at pH 11, using Calmagite as indicator (Table 12-3). Which is the principal species of Calmagite at pH 11? What color was observed before the equivalence point? After the equivalence point?

Short Answer

Expert verified

The principal species of Calmagite at pH 11 will be HIn2 Wine color was observed before the equivalence point and blue color was obtained after the equivalence point

Step by step solution

01

Information given

A titration reaction between calcium ion and EDTA at pH 11 in presence of calmagite indicator. is as follows

CaΙn+EDTACaEDTA+ΙnWineRedColorlessColorlessBlue

02

How the reaction proceeds

Little amount of indicator is induced at the beginning of the experiment. It is added to the colorless Ca2+complex and forms a red complex. After that EDTA is added. This reacts with the Ca2+ solution first.After completion of reaction between Ca2+ and EDTA, the remained indicator sample reacts with EDTA and turns into blue unbound .

03

Reason

The principal species of Calmagite at pH 11 will be HIn2-Wine color was observed before the equivalence point and blue color was obtained after the equivalence point.

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Most popular questions from this chapter

Consider the titration of 25.0 mL of 0.020 0 M MnSO4 with 0.010 0 M EDTA in a solution buffered to pH 8.00. Calculate pMn2+ at the following volumes of added EDTA and sketch the titration curve:

(a) 0 mL (b) 20.0 mL (c) 40.0 mL (d) 49.0 mL (e) 49.9 mL (f) 50.0 mL (g) 50.1 mL(h) 55.0 mL (i) 60.0 mL

Consider the titration of 25.0 mL of 0.020 0 M MnSO4 with 0.010 0 M EDTA in a solution buffered to pH 8.00. Calculate pMn2+ at the following volumes of added EDTA and sketch the titration curve:

(a) 0 mL (b) 20.0 mL (c) 40.0 mL (d) 49.0 mL (e) 49.9 mL (f) 50.0 mL (g) 50.1 mL(h) 55.0 mL (i) 60.0 mL

Give three circumstances in which an EDTA back titration might be necessary

Find pZn2+ after adding 30.0 and 51.0 mL of EDTA.

Indirect EDTA determination of cesium. Cesium ion does not form a strong EDTA complex, but it can be analyzed by adding a known excess of NaBiI4 in cold concentrated acetic acid containing excess NaI. Solid Cs3Bi2I9 is precipitated, filtered, and removed. The excess yellow is then titrated with EDTA. The end point occurs when the yellow color disappears. (Sodium thiosulfate is used in the reaction to prevent the liberated from being oxidized to yellow aqueous I2 by O2 from the air.) The precipitation is fairly selective for Cs+. The ions Li+, Na+, K+, and low concentrations of Rb+ do not interfere, although Tl+ does. Suppose that 25.00 mL of unknown containing Cs+ were treated with 25.00 mL of 0.08640 M NaBiI4 and the unreacted Bil4-required 14.24 mL of 0.0437 M EDTA for complete titration. Find the concentration of Cs+ in the unknown.

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