Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

In ion-exclusion chromatography, ions are separated from nonelectrolytes by an ion-exchange column. Nonelectrolytes penetrate the stationary phase, whereas ions of the same charge as the resin are repelled by the fixed charges. Because co-ions have access to less of the column volume, electrolytes are eluted before nonelectrolytes. The chromatogram shows the separation of trichloroacetic acid (TCA,pKa=-0.5), dichloroacetic acid (DCA,), and monochloroacetic acid (MCA,pKa=2.86) by passage through a cation-exchange resin eluted with 0.01 M HCl. Explain why the three acids are separated and why they emerge in the order shown.

Short Answer

Expert verified

Ion-exclusion chromatography: Ion exclusion chromatography is used for the separation of low molecular weight ions and some natural substances by a combination of partition, adsorption, and ion repulsion.

Step by step solution

01

Elusion order

Elution order is always from most dissociated to least dissociated species and in this case, we can see from the diagram that TCA is the first one to be separated due to the lowestpKa

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The system in Figure 26-7 can be adapted to produce the strong acid eluent methane sulfonic acid(CH3SO3-H+). For this purpose, the polarity of the electrodes is reversed and the reservoir containsNH4+CH3SO3-. The barrier membrane and the resin bed at the bottom of the figure must both be anion-exchangers loaded withCH3SO3-.Draw this system and write the chemistry that occurs in each part.

Find the milliequivalents ofH+released if100mLof26.3mMNi2+were loaded on a cation exchange column in theH+form.

Propose a scheme for separating trimethylamine, dimethylamine, methylamine, and ammonia from one another by ion-exchange chromatography.

Low iron concentration (as low as 0.02nM) in the open ocean limits phytoplankton growth. Preconcentration is required to determine such low concentrations. Tracefrom a large volume of seawater is concentrated onto achelating resin column. The column is then rinsed with 10mLof 1.5M high-purity water and eluted withofhigh-purityHNO3.

(a) For each sample, seawater is passed through the column for 17hours at 10mL/min. How much is the concentration of Fe3+in the 10mLof NHO3eluate increased by this preconcentration procedure?

(b) What is the concentration of Fe3+in the seawater when 57 nm Fe3+is found in the nitric acid eluate?

(c) Reagent-grade concentrated nitric acid is 15.7 M and contains โ‰ค0.2ppm iron. What would be the apparent concentration of Fe (nM) in a seawater blank if reagent-grade acid were used to prepare the 1.5M HNO3eluent?

26-D. Consider a capillary electrophoresis experiment conducted near pH9, at which the electroosmotic flow is stronger than the electrophoretic flow.

(a) Draw a picture of the capillary, showing the placement of the anode, cathode, injector, and detector. Show the direction of electroosmotic flow and the direction of electrophoretic flow of a cation and an anion. Show the direction of net flow.

(b) Using Table 15-1, explain why CI-has a shorter migration time than I-Predict whether Br-will have a shorter migration time than CI-or a greater migration time than I-

(c) Why is the mobility of I-greater than that ofCI-?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free