Question

Dust falls on Chicago at a rate of \(65mg{m^{ - 2}}da{y^{ - 1}}\). Major metallic elements in the dust include\(Al,Mg,Cu,Zn,Mn\), and \(Pb{.^3}Pb\) accumulates at a rate of \(0.03mg{m^{ - 2}}\) day \(^{ - 1}.\)How many metric tons (1 metric ton \( = 1000\;kg\)) of \(Pb\)falls on the 535 square kilometers of Chicago in 1 year?

Short answer

The required amount of Pb is 5.858 metric tons.

Step-by-step solution

Definition of Metallic elements and non metallic elements

• The tendency of an element to lose electrons and produce positive ions or captions is known as its metallic character.
• The most electropositive elements are alkali metals.
• The tendency of an element to receive electrons and create negative ions or anions is known as its non-metallic character.

Calculating the amount of Pb

Each year, the amount of Pb that falls\( = \left( {0.03 \times 1{0^{ - 3}}} \right)\left( {365mg/{m^2}} \right)\)\( = 10.95 \times {10^{ - 3}}\frac{{{\rm{mg}}}}{{{{\rm{m}}^2}}}.\)

Calculating the amount of Pb in kg

Then, figure out how much money you have.

The\({\rm{Pb}}\)per\(535\;{\rm{k}}{{\rm{m}}^2}\)is as shown below:

Amount of \({\rm{Pb}}\) per \(535\;{\rm{k}}{{\rm{m}}^2} = \left( {10.95 \times {{10}^{ - 3}}\frac{{{\rm{mg}}}}{{{{\rm{m}}^2}}}} \right)\left( {535 \times {{10}^6}} \right)\)\( = 5858\;{\rm{kg}}{\rm{.}}\)\(535\;{\rm{k}}{{\rm{m}}^2} = 5858\;{\rm{kg}}\)

Calculating the amount of Pb in metric tons

To convert kilograms to metric tonnes, follow the steps below:

"1 metric tonne" is a term used to describe how much something weighs\( = 1000\;{\rm{kg}}\)

Amount of \({\rm {Pb}} = 5858\;{\rm{kg}} \times \frac{{1{\rm{ metric ton }}}}{{1000\;{\rm{kg}}}}\)

\( = 5.858\;metric\;tonnes.\)