Question

Write the autoprotolysis reaction of${\mathbf{H}}_{\mathbf{2}}{\mathbf{SO}}_{\mathbf{4}}$.

Short answer

The autoprotolysis reaction for ${\mathrm{H}}_2{\mathrm{SO}}_4$is:

role="math" localid="1663387364297" $2{\mathrm{H}}_2{\mathrm{SO}}_4\rightleftharpoons {\mathrm{HSO}}_4^{-}+{\mathrm{H}}_3{\mathrm{SO}}_4^{+}$

Step-by-step solution

Definition of Autoprolysis Reaction

Auto protolysis is the process in which a proton is transported between two indistinguishable molecules. One molecule acts as a Bronsted -Lowry base, and another acts as a Bronsted Lowry acid.

Autoprolysis Reaction  

The autoprotolysis reaction for ${\mathrm{H}}_2{\mathrm{SO}}_4$ is:

$2{\mathrm{H}}_2{\mathrm{SO}}_4\rightleftharpoons {\mathrm{HSO}}_4^{-}+{\mathrm{H}}_3{\mathrm{SO}}_4^{+}$

In this reaction, two molecules of Sulfuric acid are reacted. One molecule transfers its proton to another molecule.

The proton donating molecule is said to be a Bronsted-Lowry acid, and the proton accepting molecule is a Bronsted-Lowry base.