Question

The indicator xylenol orange (Table 12-3) forms a complex with Zr(IV)in HCIsolution. Prepare a Job plot from the data in the table and suggest the stoichiometry of the complex (xylenol orange)${}_{\mathbf{x}}\mathbf{Zr}_{\mathbf{z}}$.

Short answer

The stoichiometry of the complex is$(\mathrm{xylenolorange}{)}_2{\mathrm{Zr}}_3$

Step-by-step solution

Define stoichiometry.

It is defined as the study of quantitative relations between the amount of reactants and/or products is calledstoichiometry.

Draw the graph.

Peak obtained from the graph= 0.4.

Calculate mole fraction.

We know that peak is 0.4, so mole fraction,

$0.4=\frac{2}{2+3}=\frac{\mathrm{xylenol}\mathrm{orange}}{\mathrm{xylenol}\mathrm{orange}+\mathrm{Zr}\left(\mathrm{IV}\right)}$

Therefore, The stoichiometry is,

$(\mathrm{xylenolorange}{)}_2{\mathrm{Zr}}_3$