Question

Calculate the activity coefficient of ${\mathbf{AI}}^{\mathbf{3}\mathbf{+}}$when role="math" localid="1654836623327" $\mathbf{\mu }\mathbf{=}\mathbf{0}\mathbf{.}\mathbf{083}\mathbf{}\mathbf{M}$by using linear interpolation in Table $\mathbf{8}\mathbf{-}\mathbf{1}$ .

Short answer

Thus the activity coefficient of ${\mathrm{AI}}^{3+}$when $\mathrm{\mu }=0.083\mathrm{M}$ using linear interpolation in Table $8-1\mathrm{is}0.202\mathrm{M}$

Step-by-step solution

Representation of the Table  8-1, which is used for Interpolation.

The given task is to calculate the activity coefficient of ${\mathrm{AI}}^{3+}$when $\mathrm{\mu }=0.083\mathrm{M}$using the linear interpolation in Table $8-1$.The table $8-1$is given below,

Calculating the Activity Coefficient using Interpolation.

In the task,we need to find the activity coefficient using the equation for interpolation.

$\mathrm{\gamma }=\left(\frac{0.083-0.05}{0.1-0.05}\times \left(0.18-0.245\right)\right)+0.245=0.202\mathrm{M}$

Which gives us the activity coefficient of ${\mathrm{AI}}^{3-}$when $\mathrm{\mu }=0.083\mathrm{M}$.

Thus the activity coefficient of ${\mathrm{AI}}^{3+}$ when localid="1654837296480" $\mathrm{\mu }=0.083\mathrm{M}\mathrm{is}0.202\mathrm{M}$