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Ion pairing. As in Problem 8-30, find the concentration, ionic strength, and ion pair fraction in localid="1654942556135" 0.025FNa2SO4. Assume that the size of theNaSO-4=500pm

Short Answer

Expert verified

Thus the Ionic Strength and Ion Pair Fraction of 0.025FNa2SO4 is 0.07051M and 9%

Step by step solution

01

Step 1:Calculating the Ionic Strength and Ion Pair Fraction.

This is also a task that need to be performed in the Excel. And the values will be,

Na+=0.04775โ€‰MSO2-4=0.02275MNaSO-4=0.002246M

Ionic Strength =0.070514M

Ion Pair Fraction =9%

02

Step 2:Ionic Strength and Ion Pair Fraction of 0.025  F   Na2SO4

Thus the Ionic Strength and Ion Pair Fraction of 0.025FNa2SO4 is 0.07051M and 9%

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Most popular questions from this chapter

24. Consider the dissolution of the compound,which gives X2Y22+,X2Y4+,X2Y3(aq)andY2-. Use the mass balance to find an

expression forY2-in terms of the other concentrations. Simplify

your answer as much as possible.

(a) Write the mass balance for CaCl2in water if the species areCa2+ andCI- .

(b) Write the mass balance if the species areCa2+,CI-,CaCI+ , andCaOH+

(c) Write the charge balance for part (b).

Interpolate in Table 8-1 to find the activity coefficient of H+when ฮผ=0.030M

Write the charge balance for an aqueous solution of arsenic acid, H3AsO4, in which the acid can disassociate to role="math" localid="1654936423245" H3AsO-4,HAsO42-,andAsO43-. Look up the structure of arsenic acid in Appendix G and write the structure ofHAsO2-4

Ammonia Equilibrium treated by solver. We now use the solve spreadsheet introduced in Figure 8 - 9 for TIN3 solubility to find the concentration of species in 0.01 M ammonia solution, neglecting activity coefficient. In the systematic treatment of equilibrium of NH3hydrolysis, we have four unknowns (NH3,[NH4+],H+,OH-) and two equilibrium (8-13) , (8-14). Therefore we will estimate the concentration of 4unknowns - 2equilibirum = 2species, for which I choose localid="1663566766281" NH+andOH-. Setup the spreadsheet shown below, in which the estimate localid="1663566820791" pNH4+=3.pOH-= 3 appears in B6andB7 . (Estimates comes from the Kbequilibrium 8-17 with [NH4+]=[OH-]=Kb[NH3]โ‰ˆ10-4.755[0.01]โ‡’pNH4+=pOH-โ‰ˆ3. Estimate donot have to be very good for Solver to work. The formula in cell C8 is [NH3]=[NH4+].

[OH-]/Kb and the formula in the cell C9 is [H+]=Kw/[OH-]. The mass balance b1appears in cell F6 and the charge balance b2 appears in cell F7 . Cell F8 has the sum b12+b22. As described for TIN3on page 176, open the solver window and set the Solver Option. Then use the Solver to set the target cell F8 Equal to Min by changing cells B6 : B7 . What are the concentrations of the species? What fraction of ammonia (=NH4+/NH4++NH3) is hydrolyzed. Your answer should agree with those from Goal Seek in Figure 8-8

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