Question

Write the charge balance for a solution of ${\mathbf{H}}_{\mathbf{2}}{\mathbf{SO}}_{\mathbf{4}}$in water if the${\mathbf{H}}_{\mathbf{2}}{\mathbf{SO}}_{\mathbf{4}}$ionizes ${\mathbf{H}}_{\mathbf{2}}{{\mathbf{SO}}^{\mathbf{-}}}_{\mathbf{4}}$to and${{\mathbf{SO}}^{\mathbf{2}\mathbf{-}}}_{\mathbf{4}}$

Short answer

Thus the charge balance equation for a solution of ${\mathrm{H}}_2{\mathrm{SO}}_4$in water if the ${\mathrm{H}}_2{\mathrm{SO}}_4$ionizes to ${\mathrm{H}}_2{{\mathrm{SO}}^{-}}_4$ and ${{\mathrm{SO}}^{-}}_4$ is $\left[{\mathrm{H}}^{+}\right]=\left[{{\mathrm{HSO}}_4}^{-}\right]+2\left[{{\mathrm{SO}}_4}^{2-}\right]+\left[{\mathrm{OH}}^{-}\right]$

Step-by-step solution

Step 1:Ions formed in the solutions.

In the given problem, we need to find the charge balance for a solution of ${\mathrm{H}}_2{\mathrm{SO}}_4$in water if the ${\mathrm{H}}_2{\mathrm{SO}}_4$ionizes to ${{\mathrm{HSO}}^{-}}_4$and ${{\mathrm{SO}}^{2-}}_4$

The ions formed in the solutions are given below,

Ions formed in ${\mathrm{H}}_2{\mathrm{SO}}_4:{\mathrm{HSO}}_4,{{\mathrm{SO}}_4}^{2-},{\mathrm{H}}^{+}$

Ions formed in${\mathrm{H}}_{2}O:{\mathrm{H}}^{+},{\mathrm{OH}}^{-}$

Step 2:Charge Balance Equation for the given solution.

The charge balance equation for the solution is,

$\left[{\mathrm{H}}^{+}\right]=\left[{{\mathrm{HSO}}_4}^{-}\right]+2\left[{{\mathrm{SO}}_4}^{2-}\right]+\left[{\mathrm{OH}}^{-}\right]$

Thus the charge balance equation for a solution of ${\mathrm{H}}_2{\mathrm{SO}}_4$in water if the ${\mathrm{H}}_2{\mathrm{SO}}_4$ionizes to ${{\mathrm{HSO}}^{-}}_4$and ${{\mathrm{SO}}^{2-}}_4$ is $\left[{\mathrm{H}}^{+}\right]=\left[{{\mathrm{HSO}}_4}^{-}\right]+2\left[{{\mathrm{SO}}_4}^{2-}\right]+\left[{\mathrm{OH}}^{-}\right]$