Question

Using activities, calculate the pH of a solution containing 0.010 M NaOH plus 0.012 0 M LiNO₃ . What would be the pH if you neglected activities?

Short answer

Thus the pH value for the solution containing 0.010 M NaOH plus0.012 0 M LiNO₃ is 12 .

Step-by-step solution

Step 1:Finding the pOH value.

In this problem, we need to find the pH value of a solution containing 0.010 M NaOH plus 0.012 0 M LiNO₃.

We need to note that LiNO₃ is a salt of strong base and strong acid. So the pH value is neutral.

Now we need to solve for pOH,

$$\begin{gathered} \mathrm{pOH}=-\log \left({\mathrm{OH}}^{-}\right) \\ \mathrm{pOH}=-\log \left(0.010\right) \\ \mathrm{pOH}=2 \end{gathered}$$

Step 2:Finding the pH value.

Now we can find for the pH value,

$$\begin{gathered} \mathrm{pH}=14-\mathrm{pOH} \\ \mathrm{pH}=14-2 \\ \mathrm{pH}=12 \end{gathered}$$

Thus the pH value for the solution containing 0.010 M NaOH plus 0.012 0 M LiNO₃ is 12 .