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The base B is too weak to titrate in an aqueous solution.

(a) Which solvent, pyridine or acetic acid, would be more suitable for the titration of BwithHCIO4? Why?

(b) Which solvent would be more suitable for the titration of a very weak acid with tetrabutylammonium hydroxide? Why?

Short Answer

Expert verified

(a). In the acetic acid solution,HCIO4is not leveled to the strength ofH3O'. That means that acetic acid would be more suitable for the titration of the base.

(b). Since theOHions from the tetrabutylammonium hydroxide do not react with pyridine, pyridine would be more suitable for titration.

Step by step solution

01

Define Levelling effect

Levelling effect is observed in the case of solvation of acids or bases in a solvent. Thus levelling effect is a phenomenon exhibited by solvents when an acid or base is dissolved in them.

Water forms H3O'ion which is known as a hydronium ion and it is formed when a lone pair electron on the Oxygen atom is lost to bond with the proton. Hydronium ion also behaves as acid as it is capable of losing the proton during the course of the reaction.

Any acid that is said to behave stronger acid than a hydronium ion, when dissolved in water, forms a hydronium ion with water that the strength of the acid is 'levelled' to that of the water.

Similarly,OHion is the strongest base in water. Any other base stronger than an OHion when dissolved in water its strength is levelled to that ofOHion.

02

a) Discuss the term solvent that would be more suitable for the titration

Acetic acid is a weak acid and it doesn't dissociate completely into ions in solution. When we are titrating a very weak base, we would choose to titrate it against strong acid which isHCIO4. The strong acid is not levelled to the strength of acetic acid so the presence of acetic acid as a solvent wouldn't interfere with the titration reaction. Hence acetic acid is the best choice as a solvent for the weak base.

03

b) Discuss the solvent would be more suitable for the titration of a very weak acid

Choose a strong base to titrate a very weak acid and in this case, it is tetrabutylammonium hydroxide (TBAH). Hence the suitable solvent must not interfere with the base. If acetic acid is used as the solvent, more of the hydroxide ion of TBAH is consumed by acid and the desired titration reaction will not occur due to the unavailability of the hydroxide ion. Instead, if we choose pyridine as a solvent it will not react and so this is the suitable solvent to titrate a very weak acid with TBAH.

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Most popular questions from this chapter

Calculate the pH at each point listed for the titration of 50.0 mL of 0.050 0 M formic acid with 0.0500 M KOH. The points to calculate are , 10.0, 20.0, 25.0, 30.0, 40.0, 45.0, 48.0, 49.0, 49.5, 50.0, 50.5, 51.0, 52.0, 55.0, and 60.0 mL. Draw a graph of pH versus Vb.

Titration on Diprotic Systems

11 - 30. This problem deals with the amino acid cysteine, which we will abbreviate H2C .

(a) A0.0300Msolution was prepared by dissolving dipotassium cysteine, K2Cin water. Then 40.0 mLof this solution were titrated with . Calculate the at the first equivalence point.

(b) Calculate the quotient[C2-]/[HC-] in a solution of 0.0500M cysteinium bromide (the saltH3C+Br-).

11-22. The figure compares the titration of a monoprotic weak acid with a monoprotic weak base and the titration of a diprotic acid with a strong base.

(a) Write the reaction between the weak acid and the weak base and show that the equilibrium constant is 107.78. This large value means that the reaction goes "to completion" after each addition of the reagent.

(b) Why doespK2intersect the upper curve at 32Ve and the lower curve at 2Ve? On the lower curve, "pK2"is pKathe acid, BH+.


(a) Titration of 100mL of 0.050MH2A(pK1=2.86,pK2=10.64) with 0.050 M NaOH.

(b) Titration of 100mL of the weak acid localid="1663575238403" HA(0.050M,pKa=2.86) with the weak baselocalid="1663575247899" B(0.050M,pKb=3.36).

In-1Spectrophotometry with indicators.* Acid-base indicators arc themselves acids or bases. Consider an indicator. HIn. which dissociates according to the equation

HInKaH++In-

The molar absorptivity,. is role="math" localid="1654932356442" 2080M-1cm-1for HIn and 14200M-1cm-1for In-1. at a wavelength of 440 nm.

(a) Write an expression for the absorbance of a solution containing HIn at a concentration [HIn] and role="math" localid="1654932619574" In-1at a concentration role="math" localid="1654932655635" In-in a cell of pathlength 1.00 cm. The total absorbance is the sum of absorbances of each component.

(b) A solution containing indicator at a formal concentration of role="math" localid="1654931801074" 1.84×104-Mis adjusted to pH 6.23and found to exhibit an absorbance of 0.868 at 440 nm. Calculate pKa for this indicator.

Derive the following equation for the titration of potassium hydrogen phthalate (K+HP-) with NaOH:

ϕ=CbVbCaVa=αHP-+2αP2--1-[H+]-[OH-]Ca1+[H+]-[OH-]Cb

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