Chapter 8: Problem 132
Molar conductivity of a solution of an electrolyte \(A B_{3}\) is \(150 \mathrm{Scm}^{2} \mathrm{~mol}^{-1}\). If it ionises as \(\mathrm{AB}_{3} \longrightarrow A^{3+}+3 B^{-}\), its equivalent conductivity will be : (a) \(150\left(\right.\) in \(\mathrm{Scm}^{2} \mathrm{eq}^{-1}\) ) (b) 75 (in \(\mathrm{Scm}^{2} \mathrm{eq}^{-1}\) ) (c) 50 (in \(\mathrm{Scm}^{2} \mathrm{eq}^{-1}\) ) (d) 80 (in \(\mathrm{Scm}^{2} \mathrm{eq}^{-1}\) )
Short Answer
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