Chapter 5: Problem 52
Relation between reactant and major product obtained in the following reaction
is
Short Answer
Step by step solution
Identify the starting compound
Investigate the first reaction step (i: 8H/Δ)
Investigate the second reaction step (ii: N2H4)
Investigate the third reaction step (iii: OH/Δ)
Investigate the fourth reaction step (iv: O3, Zn)
Compare the reactant and major product
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
SMILES Notation in Organic Chemistry
SMILES strings encode the atom and bond information required to recreate the molecular structure:
- Atoms are represented by their chemical symbols.
- Bonds are usually implied by the order of the letters, but double and triple bonds can be indicated with "=" and "#" respectively.
- Branches and cyclic structures are described using specific punctuation symbols like parentheses and numbers.
Clemmensen Reduction
Typically, Clemmensen reduction involves the reaction of the carbonyl compound with zinc amalgam and concentrated hydrochloric acid. Here's a breakdown of the process:
- The ketone or aldehyde is combined with zinc amalgam, a combination of zinc and mercury.
- Concentrated hydrochloric acid is applied, which facilitates the reduction.
- The carbonyl group (C=O) is transformed into a methylene group (CH2).
Wolff-Kishner Reduction
Here's how the Wolff-Kishner reduction works:
- Hydrazine reacts with the carbonyl group to form a hydrazone.
- Under strong basic conditions and heat, nitrogen gas is eliminated.
- This results in the conversion of the carbonyl bond (C=O) into an alkane bond (C-H).
Ozonolysis Reaction
In an ozonolysis reaction:
- Ozone attacks the double bond of alkenes or alkynes.
- The intermediate ozonide is unstable and is generally reduced using a reductive workup such as zinc and water, or another reducing agent.
- Results in the cleavage of the double bond, producing two carbonyl fragments.