Chapter 5: Problem 31
\(\mathrm{CH}_{3} \mathrm{CHO}\) can be converted into carboxylic acid or acid salt by using (A) \(\mathrm{NaOI}\) (B) \(\mathrm{CH}_{3} \mathrm{CO}_{3} \mathrm{H}\) (C) \(\mathrm{Ag}_{2} \mathrm{O}\) (D) \(\mathrm{NaOH}\)
Short Answer
Expert verified
In conclusion, from the given reagents, only (A) \(\mathrm{NaOI}\) can successfully convert acetaldehyde into a carboxylic acid or acid salt.
Step by step solution
01
Identifying Acetaldehyde
We are given the compound \(\mathrm{CH}_{3} \mathrm{CHO}\), which is known as acetaldehyde. It contains a carbonyl group (C=O) with one hydrogen bonded to the carbonyl carbon.
02
Analyzing Reagent (A)
Reagent (A) is \(\mathrm{NaOI}\), which is sodium hypoiodite. This is a mild oxidizing agent that can oxidize aldehyde groups to carboxylic acids. Thus, when reacting acetaldehyde with sodium hypoiodite, it forms acetic acid (carboxylic acid) or its corresponding acid salt. So, (A) is a correct answer.
03
Analyzing Reagent (B)
Reagent (B) is \(\mathrm{CH}_{3} \mathrm{CO}_{3} \mathrm{H}\), which is peracetic acid. Peracetic acid is a strong oxidizing agent, but it selectively oxidizes primary alcohols to aldehydes. Therefore, it will not further oxidize acetaldehyde to a carboxylic acid or salt. So, (B) is not a correct answer.
04
Analyzing Reagent (C)
Reagent (C) is \(\mathrm{Ag}_{2} \mathrm{O}\), which is silver oxide. Silver oxide is a weak oxidizing agent, insufficient to oxidize acetaldehyde to a carboxylic acid or salt. So, (C) is not a correct answer.
05
Analyzing Reagent (D)
Reagent (D) is \(\mathrm{NaOH}\), which is sodium hydroxide. Sodium hydroxide is a strong base and can form a salt with carboxylic acids. However, it is not an oxidizing agent, so it is unable to convert acetaldehyde to a carboxylic acid or salt. So, (D) is not a correct answer.
In conclusion, from the given reagents, only (A) \(\mathrm{NaOI}\) can successfully convert acetaldehyde into a carboxylic acid or acid salt.
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with Vaia!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Sodium Hypoiodite
Sodium hypoiodite, denoted as \(\mathrm{NaOI}\), plays an intriguing role in organic chemistry as a mild oxidizing agent. This chemical compound comprises sodium, oxygen, and iodine and is typically used in oxidation reactions where control is essential. During the oxidation of acetaldehyde \((\mathrm{CH}_3 \mathrm{CHO})\), sodium hypoiodite plays a pivotal role.
In simple terms, when sodium hypoiodite is introduced to an aldehyde like acetaldehyde, it helps remove hydrogen from the aldehyde group \((\mathrm{-CHO})\). This process transforms the original substance into a carboxylic acid or its corresponding acid salt by adding an oxygen atom to form a carboxyl group \((-COOH)\).
In simple terms, when sodium hypoiodite is introduced to an aldehyde like acetaldehyde, it helps remove hydrogen from the aldehyde group \((\mathrm{-CHO})\). This process transforms the original substance into a carboxylic acid or its corresponding acid salt by adding an oxygen atom to form a carboxyl group \((-COOH)\).
- Aldehyde: Initial compound with a \((-CHO)\) group.
- Carboxylic Acid: Resulting compound with \((-COOH)\) and increased oxidation.
Organic Oxidation Reactions
Organic oxidation reactions involve the process of increasing the oxygen content or reducing the hydrogen content of a compound. It usually transforms a less oxidized compound into a more oxidized one. In organic chemistry, gaining an understanding of this oxidation process is crucial as it leads to various functional group conversions.
Thus, when learning about organic oxidation reactions, understanding the choice of reagent is key. Different oxidizing agents like sodium hypoiodite, silver oxide, and peracetic acid have varying capabilities. Sodium hypoiodite can specifically assist in converting aldehydes to carboxylic acids, demonstrating its unique utility in organic synthesis.
- Primary Alcohols can be converted to Aldehydes.
- Aldehydes can be further oxidized to Carboxylic Acids.
Thus, when learning about organic oxidation reactions, understanding the choice of reagent is key. Different oxidizing agents like sodium hypoiodite, silver oxide, and peracetic acid have varying capabilities. Sodium hypoiodite can specifically assist in converting aldehydes to carboxylic acids, demonstrating its unique utility in organic synthesis.
Aldehyde to Carboxylic Acid Conversion
The conversion of aldehydes into carboxylic acids is an essential chemical transformation, commonly achieved by oxidation reactions. Aldehydes have a hydrogen atom bonded to a carbonyl group \((-CHO)\), while carboxylic acids have an added hydroxyl group \((-COOH)\), accounting for the extra oxygen and higher oxidation state.
This conversion is mostly pursued for creating either the free acid or the corresponding acid salt, making the reaction significant for many industries. Choosing the correct oxidizing agent is crucial to obtain the carboxylic acid efficiently.
This conversion is mostly pursued for creating either the free acid or the corresponding acid salt, making the reaction significant for many industries. Choosing the correct oxidizing agent is crucial to obtain the carboxylic acid efficiently.
- Sodium Hypoiodite: Converts aldehydes to carboxylic acids.
- Reaction Efficiency: Minimizes by-products due to mildness.